Okay I will have an example for you. 3 and 2/7. STEP 1) multiply the denominator by the whole number. 3×7=21. STEP 2) add the numerator to 21. 21+2=23. STEP 3) 23 is the new numerator so put 23 over 7. FINAL SOLUTION 23/7.
Answer:
(5.4582 ; 6.8618)
Step-by-step explanation:
Given the data:
6 10 2 6 3 3 3 6 6 6 6 5 8 9 10 10 7 9 3 6 5 10 9 9 10 3 8 6 6 3 3 6 6 5 4 10 9 3 5 7 10 6 3 8 6 8 3 3 5 5
Sample mean, xbar = Σx / n
n = sample size = 50
ΣX = 308
xbar = 308 / 50 = 6.16
Using a Calculator :
The sample standard deviation, s = 2.469
Confidence interval = xbar ± margin of error
Margin of Error = Tcritical * s/sqrt(n)
Tcritical at 95% ; df = 50 - 1 = 49
Tcritical = 2.010
Hence,
Margin of Error= 2.010 * (2.469/sqrt(50)) = 0.7018
Lower boundary : (6.16 - 0.7018) = 5.4582
Upper boundary : (6.16 + 0.7018) = 6.8618
(5.4582 ; 6.8618)
Answer:
she is paying back 9112.5 R.O
Interest paid back is 2,403.95
Step-by-step explanation:
To find the amount, we use the compound interest formula.
This is given as;
A = I( 1 + r/n)^nt
where A is the amount we are trying to calculate
I is money borrowed = 6709
r is the interest rate = 12 1/3% = 37/3 = 12.33% which is same as 12.33/100 = 0.1233
n is the number of times interest is compounded. We have 15 2 months in 2 and a half years
t is the number of years = 2.5
Plugging these values, we have;
A = 6709(1 + 0.1233/15)^(15)(2.5)
A = 6709(1.0082)^(37.5)
A = 9112.95 R.O
Interest is amount - principal( money borrowed)
9112.95 - 6709 = 2403.95
-m-4=-13
-m=-13+4=-9
m=9
☺☺☺☺
Answer:
It's 15
i took the test
Step-by-step explanation:
