All categories

1 year ago

I need help with compatible numbers using division 413÷59

Mathematics

1 answer:

9966 [12]1 year ago

8 0

we have the following:

$\frac{413}{59}=7$

Since the result is an exact number, they are compatible numbers

You might be interested in

6- 6x^2- 3x = 0 solve

VARVARA [1.3K]

Answer:

The solutions are $x=\frac{3)+\sqrt{153} }{-12}$ , $x=\frac{3)-\sqrt{153} }{-12}$

If you need to have them in a decimal form rounded to 3 decimals, the answers would be $x=-1.281$ , $x=0.781$

Step-by-step explanation:

We are given the equation $6-6x^2-3x=0$

The first thing that can be done is to rearrange the terms so that they are in descending order of power. This makes it easier to work with

This gives us $-6x^2-3x+6=0$

To find the solutions to this equation, we can use the quadratic formula, which will tell us that the solutions are equal to $\frac{-b+\sqrt{b^2-4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}$

From our equation, we can gather that $a=-6, b=-3, c=6$

Now that we have our variables, we can plug them into the quadratic formula to get our solutions.

$\frac{-(-3)+\sqrt{(-3)^2-4(-6)(6)} }{2(-6)}\\\\\frac{3)+\sqrt{9+144} }{-12}\\\\\frac{3)+\sqrt{153} }{-12}$

And now for our second equation

$\frac{-(-3)-\sqrt{(-3)^2-4(-6)(6)} }{2(-6)}\\\\\frac{3)-\sqrt{9+144} }{-12}\\\\\frac{3)-\sqrt{153} }{-12}$

3 0

3 years ago

Cindy was asked by her teacher to subtract 3 from a certain number and then divide the result by 9. Instead, she subtracted 9 a

butalik [34]

The answer is 11 i think
102-9=93%3=31
102-3=99%9=11

4 0

3 years ago

Powers of _____ will only contain 1s and 0s?

melamori03 [73]

Powers of 10 will only contain 1s and 0s

5 0

3 years ago

Do the following scenarios match the equation y=2x+5

Aneli [31]

Where are the scenarios?

3 0

4 years ago

Read 2 more answers

Use the function table to determine the slope.EXPLAIN YOUR THINKING AND HOW YOU GOT YOUR ANSWER.I WILL MARK YOU BRAINLIST!

Tom [10]

Answer:

3¼

Step-by-step explanation:

$formula \frac{{y}^{2} - {y}^{1} }{ {x}^{2} - {x}^{1} }$

We take any of the two points shown in the question. I will take (-3, 1) and (1, 14).

x¹ = -3

y¹ = 1

x² = 1

y² = 14

Now, we sub these figures into the formula.

$\frac{14 - 1}{1 - ( - 3)}$

This leaves us with 14-1/1+3, which we can make into 13/4

13/4 = 3¼

Disclaimer: It is not actually x (or y) in the power of two, but a way to distinguish one x (or y) from the other. It is a label of sorts.

3 0

3 years ago

Read 2 more answers