Answer:
1) 
2) 
3) 
Step-by-step explanation:
So we have the two functions:

And we want to find (f+g)(x), (f-g)(x), and (f*g)(x).
1)
(f+g)(x) is the same to f(x)+g(x). Substitute:

Combine like terms:

Add:

So:

2)
(f-g)(x) is the same to f(x)-g(x). So:

Distribute:

Combine like terms:

Simplify:

So:

3)
(f*g)(x) is the same to f(x)*g(x). Thus:

Distribute:

Distribute:

Combine like terms:

Simplify:

So:

0, 1/8, 1/4, 1/2, 1/2, 3/4, 1, 4/3, 3, 3, 7/2, 9, 32/3, 15, hope this helps :)
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Answer: so a can be -2 and b can be 6, note that there are many combinations since u can factor all types of stuff out including fractions
Step-by-step explanation:
a(bx+3) basically is just factoring out a random common factor between -12x and -18
so we can factor out a -2 to get -2(6x+9)