Answer:
Part 1) The quadratic equation has zero real solutions
Part 2) The solutions are
and
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
The discriminant is equal to

If D=0 -----> the quadratic equation has only one real solution
If D>0 -----> the quadratic equation has two real solutions
If D<0 -----> the quadratic equation has two complex solutions
<em>Find the value of D</em>
-----> the quadratic equation has two complex solutions
<em>Find out the solutions</em>
substitute the values of a,b and c in the formula
Remember that

Multiply by 100, as per cent means per 100.
The mean of the data is 15 all you gotta do is add all the number up and divide by the numbers added
Move the negative sign to the left
-x/5 = -20
Multiply both sides by 5
-x = -20 × 5
Simplify 20 × 5 to 100
-x = -100
Multiply both sides by -1
<em>x = 100</em>
<u>C. 100</u>
base is a square 16m 6m
Step-by-step explanation:
A square is a regular quadrilateral and it has four equal sides and four equal angles (90 degree angle or right angles).
A square quadrilateral with vertices ABCD would be denoted by ABCD. The perimeter of a square (quadrilateral) is given by:
P = 4a
Where a is the length of each side.
Perimeter of the square:
P = 4a
P = 4 × 16 cm
P = 64 cm
Hence, the perimeter of square is 64 cm.