The problem can be translated into an equation that is something like 4/5 + 3/x = 1/2
we cannot have x equal to zero because the number can be infinite.
So the LCD here is 10x, so multiply both sides by that to get:
8x + 30 = 5x
Subtract 5x and 30 from both sides:
3x = -30
divide:
x = -10
The solution isn't zero so there is a solution.
Answer:
Bro
Step-by-step explanation:
sorry
Answer:
The measures of the angles are 150° and 30°.
Step-by-step explanation:
Let x and y represent the measures of the angles, with x representing the larger angle.
x + y = 180 . . . . . . the two angles are supplementary
x = 90 + 2y . . . . . one is 90° more than twice the other
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Substituting the expression given by the second equation into the first, we have ...
(90 +2y) +y = 180
3y = 90 . . . . . . . . . . collect terms, subtract 90
y = 30 . . . . . . . . . . . divide by the coefficient of y
x = 180 -y = 150
The measures of the angles are 150° and 30°.
