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Andre45 [30]
1 year ago
11

Question:70% of x is 63. 1.Write an equation that shows the relationship of 70%, x, and 63. 2. Use your equation to find x. Show

your reasoning.
Mathematics
1 answer:
a_sh-v [17]1 year ago
3 0

"x" represents an unknown number, we know that 70% of x equals 63.

To calculate the percentage of a number you have to multiply the said number by the percentage, in this case, 70%, and divide the result by 100:

So the 70% of x can be calculated as:

\frac{70\cdot x}{100}=63

You can simplify this expression by solving the division

\begin{gathered} \frac{70}{100}x=63 \\ \frac{7}{10}x=63 \\ 0.7x=63 \end{gathered}

Then the expression that shows you the relationship is

0.7x=63

Using this expression you can determine the value of x, to do so you have to divide both sides of the equal sign by 0.7

\begin{gathered} \frac{0.7x}{0.7}=\frac{63}{0.7} \\ x=90 \end{gathered}

The value of x is 90

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y-4 = 2(x-1)

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What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
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Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

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The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

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9(x+3)-(2x+5)

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Step-by-step explanation:

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