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hram777 [196]
1 year ago
7

What are the alternate angle pairs in the picture below ?

Mathematics
1 answer:
polet [3.4K]1 year ago
5 0

Given:

is the transversal that intersects the lines r and s.

Required:

Pairs of alternate exterior angles.

Explanation:

Line q intersects the lines r and s.

The alternate exterior angles are,

\angle2\text{ and }\angle8\text{ , }\angle1\text{ and }\angle7

Answer:

Thus the required answer is option 2.

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Solve the system of equations. y=23x–19 x2–y= – 6x–23 Write the coordinates as integers, simplified proper or improper fractions
forsale [732]

Answer:

(3, 50) and (14,303)

Step-by-step explanation:

Given the system of equations;

y=23x–19 ....1

x²–y= – 6x–23 ...2

Substitute 1 into 2;

x²–(23x-19)= – 6x–23

x²–23x+19= – 6x–23 .

x²-23x + 6x + 19 + 23  = 0

x² - 17x + 42 = 0

Factorize;

x² - 14x - 3x + 42 = 0

x(x-14)-3(x-14) = 0

(x-3)(x-14) = 0

x = 3 and 14

If x = 3

y = 23(3) - 19

y = 69-19

y = 50

If x = 14

y = 23(14) - 19

y = 322-19

y = 303

Hence the coordinate solutions are (3, 50) and (14,303)

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3 years ago
Simply: -2 1/3 - (-10 1/6)
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Answer: 7.83

Step-by-step explanation:

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The measure of an exterior angle of a triangle is equal to which of the following measures?​
Korolek [52]

Measures of sum of the two opposite angles.

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What is the following sum? Assume x20 and 20.<br> √√x²y³ +2√√x³y² + xy √√y
max2010maxim [7]

The value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

<h3>How to evaluate the sum?</h3>

The attachment represents the proper format of the question

The summation expression is given as:

\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y

Expand the radicands

\sqrt{x^2y^2 * y} + 2\sqrt{x^2y^4* x} + xy\sqrt y

Evaluate the square roots

xy\sqrt{y} + 2xy^2\sqrt{x} + xy\sqrt y

Add the like terms

2xy\sqrt{y} + 2xy^2\sqrt{x}

Hence, the value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

Read more about expressions at:

brainly.com/question/723406

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