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hram777 [196]
1 year ago
7

What are the alternate angle pairs in the picture below ?

Mathematics
1 answer:
polet [3.4K]1 year ago
5 0

Given:

is the transversal that intersects the lines r and s.

Required:

Pairs of alternate exterior angles.

Explanation:

Line q intersects the lines r and s.

The alternate exterior angles are,

\angle2\text{ and }\angle8\text{ , }\angle1\text{ and }\angle7

Answer:

Thus the required answer is option 2.

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I need yo help B, on dis question
Anna71 [15]
For this case we can use the law of the sine to solve the problem.
 We have then:
 5 / sine (68) = 5 / sine (x)

 From here, we clear the value of x.
 We have then:
 sine (x) = (5/5) * (sine (68))

 Rewriting we have:
 sine (x) = (1) * (sine (68))

sine (x) = sine (68)

x = arcsine (sine (68))

x = 68
 Answer:
 
The angle R is given by:
 
x = 68 degrees
 
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6. The equation of line A is 3x + 6y - 1 = 0. Give the equation of a line that passes through the
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Step 1: Convert to slope-intercept form to find the slope of the line.

This isn't necessary if you know all the shortcuts, it just makes your life a bit easier.

3x+6y-1=0\\6y=-3x+1\\y=-\frac{3}{6}x+\frac{1}{6}\\-\frac{1}{2}x+\frac{1}{6}

Now we want to find the equations for our new lines. It's easiest to do this in slope-intercept form, so let's start finding the slope and y-intercept.

So for the perpendicular line, the slope is going to flip and change signs, this is aka its opposite reciprocal.
And for the parallel line, it'll stay the same.

-\frac{1}{2} ⇒ \frac{2}{1}=2
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As for the y-intercept, just apply that slope until you get a point where x=0.

(5, 1) with a rise of 2 and a run of 1...let's work backwards to (0, b)
(5, 1), (4, -1), (3, -3), (2, -5), (1, -7), (0, -9).

(5, 1) with a rise of -1 and a run of 2...let's work backwards to (0, b)
(5, 1), (3, 0), (1, -1)...gonna have to take half a step here...(0, -1.5).

Now let's construct our equations in slope-intercept form.

y = 2x-9\\y=-\frac{1}{2}x-\frac{3}{2}

And now it's time to convert to general form!

Make sure we have common denominators...check.

Multiply by the denominator...

y=2x-9\\2y=1x-3

...check.

Aaaand bring everything over!

\boxed{-2x+y-9=0}\\\boxed{-x+2y-3=0}

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Answer:

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Step-by-step explanation:

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Tresset [83]

Answer:

-4/8 i think

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