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avanturin [10]
3 years ago
9

KFC sells whole chicken dinners for 12 and half chicken dinners for 8. Yesterday it sold a total of 400 dinners and took in 4200

. How many of each size dinner were sold? What were the cedi sales of each size dinner?​
Mathematics
1 answer:
SVEN [57.7K]3 years ago
5 0

Answer:

150 half chicken and 250 full chicken

Step-by-step explanation:

Represent whole chicken with w and half chicken with h.

So, we have:

Total = 400

Which implies that:

w + h = 400

Also:

Amount =\$4200

Which implies that:

12w + 8h = 4200

So, we are to solve for h and w from:

w + h = 400

12w + 8h = 4200

Make h the subject in the first equation

h = 400 - w

Substitute 400 - w for h in the second equation

12w + 8(400 - w) = 4200

12w -8w + 3200 = 4200

12w -8w =- 3200 + 4200

4w =1000

w = 250

Recall that:

h = 400 - w

h = 400 - 250

h =150

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Answer:

13.60units

Step-by-step explanation:

Given data

U(-7,5) and V(4, -3)

x1=-7

y1=5

x2= 4

y2= -3

The expression for the distance between two points is

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((4-(-7))²+(-3-5)²)

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d=√(11)²+(-8)²)

d=√121+64

d=√185

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Step-by-step explanation:

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In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

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