Answer:
13.60units
Step-by-step explanation:
Given data
U(-7,5) and V(4, -3)
x1=-7
y1=5
x2= 4
y2= -3
The expression for the distance between two points is
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((4-(-7))²+(-3-5)²)
d=√((4+7))²+(-8)²)
d=√(11)²+(-8)²)
d=√121+64
d=√185
d=13.60units
Hence the distance is 13.60units
Sawarasenai kimi wa shoujo na no?~
Boku Wa yaRcHin BiCChi nO oSu Da YO!~~
Answer: 80, 1/12, 5/6
Step-by-step explanation:
Considering that the addresses of memory locations are specified in hexadecimal.
a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ ) = 65536 memory locations
b) The range of hex addresses in a microcomputer with 4096 memory locations is ; 4095
<u>applying the given data </u>:
a) first step : convert FFFF₁₆ to decimal ( note F₁₆ = 15 decimal )
( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )
= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )
= 61440 + 3840 + 240 + 15 = 65535
∴ the memory locations from 0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations
b) The range of hex addresses with a memory location of 4096
= 0000₁₆ to FFFF₁₆ = 0 to 4096
∴ the range = 4095
Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.
Learn more : brainly.com/question/18993173