Find MN , i need it please and thanks

Jason paints 1/4 of the area of his living room walls,w,on Monday. On Tuesday, he paints twice as much as he painted on Monday.

zepelin [54]

1 - (1/4 + 2*1/4)
1 - 3/4
1/4 of the living room still remains unpainted.

8 0

3 years ago

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A baker made 35 pastries in 3 1/2 hours. how many pastries dod the baker make in one hour?

Sophie [7]

Answer:

10 pastries

Step-by-step explanation:

To find how many they made in 1 hour, divide 35 by 3 1/2

35/3.5

= 10

So, he made 10 pastries in 1 hour

6 0

3 years ago

How to write an equation for the line perpendiculer and trhough the given ppoint?

valentinak56 [21]

A method that always works is to find the slope of the given line, then find the negative reciprocal of that. Your result will be the slope of the perpendicular line. Using this slope and the given point, fill in the parameters of the point-slope form of the equation of a line.

For m = slope of given line and (h, k) = given point, the perpendicular line will be
y = (-1/m)(x -h) +k

Often, this equation can be simplified to another appropriate form, such as slope-intercept form (y = mx+b) or standard form (ax+by=c).

_____
The slope of a given line can be found by solving its equation for y. The slope is the coefficient of x in that solution. If the given line is characterized by two points, (x1, y1) and (x2, y2), then its slope is m = (y2-y1)/(x2-x1).

In the unusual case where the given line is vertical (x=<some constant>), the slope of the perpendicular line is zero, and the line you want becomes y=k.

5 0

3 years ago

8 squared by 6 ÷ 4 squared by 3 =

loris [4]

8^6 ÷ 4^3

8^6 = 262,144

4^3 = 64

So, 262,144 ÷ 64 = 4,096.

Done!

3 0

3 years ago

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A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A

julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

$D^{2} = (90 - x)^{2} + 90^{2}$ (1)

$\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}$

$2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}$

$D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}$ (2)

Since:

$D = \sqrt{(90 -x)^{2} + 90^{2}}$

When x = 45 (the batter is halfway to first base), D is:

$D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62$

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

$100.62 \frac{d(D)}{dt} = -(90 - 45)*31$

$\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s$

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

$D^{2} = 90^{2} + x^{2}$