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Olenka [21]
1 year ago
12

a sample container of carbon monoxide occupies a volume of 422 ml at a pressure of 785 torr and a temperature of 242 k. what wou

ld its temperature be if the volume were changed to 225 ml at a pressure of 785 torr?
Chemistry
1 answer:
MrRissso [65]1 year ago
4 0

The temperature if the volume were changed to 225 ml at a pressure of 785 torrs is 129K.

Pressure is constant.

so

V1 /  T1 = v2 / T2

so

T2 = V2 T1 / V1

T2 =  225 x 242 / 422

T2 =  129K

What is temperature?

Temperature is a measure of hotness or coldness expressed on several scales, including Fahrenheit and Celsius. Temperature indicates the direction in which thermal energy spontaneously flows - ie, from a hotter body (one at a higher temperature) to a colder body (another at a lower temperature).

The Fahrenheit temperature scale (°F) is used in the United States and some other English-speaking countries. The Celsius temperature scale (°C) is standard in almost all countries that have adopted the metric system and  is widely used in science. The Kelvin (K) scale, the absolute temperature scale is recognized as the international standard for scientific temperature measurement.

To learn more about temperature, refer;

brainly.com/question/15267055

#SPJ4

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Explanation: b

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Determine the mass of CuSO4 • 5H20 that must be used to prepare 250mL of 2.01 M CuSO4(aq).
mario62 [17]

Given parameters:

Volume of CuSO₄ = 250mL

Concentration of CuSO₄ = 2.01M

Unknown:

Mass of CuSO₄.5H₂O = ?

To solve this problem, we must write the chemical relationship between both species.;

             CuSO₄.5H₂O  →   CuSO₄ + 5H₂O

Now that we know the expression, it is possible to solve for the unknown mass.

First find the number of moles of CuSO₄;

         Number of moles  = Concentration x Volume

Take 250mL to L so as to ensure uniformity of units;

           Volume  = 250 x 10⁻³L

  Input the parameters and solve for number of moles;

        Number of moles  = 250 x 10⁻³  x  2.01 = 0.5mol

From the equation;

             1 mole of CuSO₄ is produced from 1 mole of CuSO₄.5H₂O  

So  0.5 moles of CuSO₄ will be produced from 0.5 moles of CuSO₄.5H₂O

Now let us find the molar mass of CuSO₄.5H₂O = 63.6 + 32 + 4(16) + 5(2x1 + 16)  = 249.6g/mole

Mass of CuSO₄.5H₂O = number of moles x molar mass

                                      = 0.5 x 249.6

                                     = 124.8g

The mass of CuSO₄.5H₂O is 124.8g

5 0
3 years ago
Explain what helps convert non-rich oxygen blood cells back to oxygen rich cells?
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Answer:

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Explanation:

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Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low
LenaWriter [7]

Answer:

Compound B has greater molar mass.

Explanation:

The depression in freezing point is given by ;

\Delta T_f=i\times k_f\times m..[1]

m=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in kg}}

Where:

i = van't Hoff factor

k_f = Molal depression constant

m = molality of the solution

According to question , solution with 5.00 g of A in 100.0 grams of water froze at at lower temperature than solution with 5.00 g of B in 100.0 grams of water.

The depression in freezing point of solution with A solute: \Delta T_{f,A}

Molar mass of A = M_A

The depression in freezing point of solution with B solute: \Delta T_{f,B}

Molar mass of B = M_B

\Delta T_{f,A}>\Delta T_{f,B}

As we can see in [1] , that depression in freezing point is inversely related to molar mass of the solute.

\Delta T_f\propto \frac{1}{\text{Molar mass of solute}}

M_A

This means compound B has greater molar mass than compound A,

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Which will have the lowest boiling point between pure water, 0.5NacI, 1.0 NaCi or 2.0 NaCi?
Andru [333]

Answer:

pure water will have the lowest boiling point.

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