Hello!
Reading the worksheet shows you how to find the concentration of liquid water in a substance, but when converting a decimal to a percentage, remember that ALL percentages are out of 100, so, we multiply the decimal by 100 to convert it into a percentage.
Liquid A: total amount: 10 millimeters & amount of water: 7 millimeters
7/10 = 0.7 × 100 = 70%
Liquid B: total amount: 100 millimeters & amount of water: 92 millimeters
92/100 = 0.92 × 100 = 92%
Liquid C: total amount: 15 millimeters & amount of water: 13 millimeters
13/15 = 0.867 × 100 = 86.7%
Liquid D: total amount: 28 millimeters & amount of water: 22 millimeters
22/28 = 0.786 × 100 = 78.6%
<u>Final answers</u>:
- Liquid A: 70%
- Liquid B: 92%
- Liquid C: 86.7%
- Liquid D: 78.6%
The answer is 1) gained
Always <span><span>think "into" for "endo" (energy goes in), and "exit" for "exo" (energy is released).</span> </span>
Hope it helps ^-^
For the answer to the question above, since the process is carried out at constant pressure,
<span>work = P (V1-V2) </span>
<span>= 1.3 E5 (6-12) = -7.8 E5 N.m (in this case the work is made by the system, so it is negative if work made on the system then it should be positive)</span>
In CO2 the dipole moments cancel out, while in H20, they don’t, making it polar. In C02, both oxygens are more electronegative than the carbon, but they pull equally apart from one another, so there is no dipole moment (the pulls cancel)
The answer is refining which is c
