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2 years ago

What is the molality of a solution containing 8.0 grams of solute in 0.50 kg of solvent?

2 answers:

5 0

Molality= moles/ Kg of solvent

You need to change the grams to moles. Since you did not say what the solute is, I can't change the grams to moles.

sveta [45]2 years ago

5 0

Answer:

0.67m

Explanation:

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Together oxygen and nitrogen comprise what percentage of the atmosphere

Charra [1.4K]

Oxygen is 21% and nitrogen is 78% so combined is 99%

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2 years ago

This is the elliptical orbit of the Earth around the sun. It takes 365.26 days to complete one orbit.

nydimaria [60]

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3 years ago

Read 2 more answers

- How many grams are in 4.6 x 1016 molecules of phosphorus trichloride (PCI)?

MariettaO [177]

Answer:

0.0000101 grams.

Explanation:

First of all, use Avogadro's number to convert from molecules to moles.

Avogadro's number is 6.02 x 10^23.

Second of all, to convert from moles to grams, find the substance formula of phosphorus trichloride. After finding the substance formula, then find the molar mass of phosphorus trichloride.

Phosphorus trichloride is PCl3

Now find the molar mass of PCl3

P = 31.0 amu

Cl = 35.5 amu

They are three chlorine atoms and one phosphorus atom. So you do this.

31.0(1) + 35.5(3) = 137.5 g/mol

Now use dimensional analysis to show your work

4.6 x 10^16 grams of PCl3 * 1 mol/ 6.02 x 10^23 * 137.5 g/mol / 1 mol

The grams and the moles cancel out.

So now do [(4.6 x 10^16) / (6.02 x 10^23)] x 137.5

and you will get 0.000010507

4.6 has the fewest digits which is 2.

So use sig figs and the answer rounds to the nearest millionths.

0.000010507 rounds to 0.0000101

So the final answer is 0.0000101 grams(don't forget the units)

Hope it helped!

4 0

2 years ago

The initial pressure of a mixture of C6H6 and an excess of H2 in a rigid vessel is 1.21 atm. A catalyst is introduced. After the

KengaRu [80]

Answer:

mole fraction of C6H6 = 0.613 atm

Explanation:

The equation for this reaction is :

$C_6H_6 _{(g)} + 3H_2_{(g)} \to C_6H_{12}_{(g)}$

Initial P₁ P₂ 0

Final 0 P₂ -P₁/2 P₁

After completion of the reaction;

P₁ + P₂ = 1.21 atm ----- (1)

P₂ - P₁/2 + P₁ = 0.839 atm

P₂ + P₁/2 = 0.839 atm ----- (2)

Subtracting (2) from (1); we have:

P₁/2 = 0.371

P₁ = 0.742 atm

From(1)

P₁ + P₂ = 1.21 atm

0.742 atm + P₂ = 1.21 atm

P₂ = 1.21 atm - 0.742 atm

P₂ = 0.468 atm

Thus, the partial pressure of C6H6 = 0.742 atm

∴

Partial pressure = Total pressure × mole fraction of C6H6

mole fraction of C6H6 = Partial pressure / Total pressure

mole fraction of C6H6 = 0.742 atm / 1.21 atm

mole fraction of C6H6 = 0.613 atm

5 0

2 years ago

Which situations will NOT increase the reactions rate of most chemical reactions?

jenyasd209 [6]

Answer:

Reactant concentration. Increasing the concentration of one or more reactants will often increase the rate of reaction. ...

Physical state of the reactants and surface area. ...

Temperature. ...

Presence of a catalyst.

Explanation:

Five factors typically affecting the rates of chemical reactions will be explored in this section: the chemical nature of the reacting substances, the state of subdivision (one large lump versus many small particles) of the reactants, the temperature of the reactants, the concentration of the reactants

5 0

2 years ago