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AveGali [126]
3 years ago
5

5.0 gram of anhydrous calcium carbonate is reacted with an excess of dilute nitric acid. if the reaction is carried out at 25 de

grees and 100 kPa, calculate the volume of dry gas that would be produced
Chemistry
1 answer:
Aneli [31]3 years ago
6 0

Answer:

I don’t know

Explanation:

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A solution is prepared by dissolving 27.7 g of cacl2 in 375 g of water. the density of the resulting solution is 1.05 g/ml. the
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The answer is 6.88.
Solution:
We can calculate for the percent composition of CaCl2 by mass by dividing the mass of the CaCl2 solute by the mass of the solution and then multiply by 100. The total mass of the resulting solution is the sum of the mass of CaCl2 solute and the mass of water solvent. Therefore, the percent composition of CaCl2 by mass is 
     % by mass = (mass of the solute / mass of the solution)*100 
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                        = (27.7 g CaCl2 / 27.7g + 375g) * 100 
                        = 6.88
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