Answer:
- The shaded region is 9.83 cm²
Step-by-step explanation:
<em>Refer to attached diagram with added details.</em>
<h2>Given </h2>
Circle O with:
- OA = OB = OD - radius
- OC = OD = 2 cm
<h2>To find</h2>
<h2>Solution</h2>
Since r = OC + CD, the radius is 4 cm.
Consider right triangles OAC or OBC:
- They have one leg of 2 cm and hypotenuse of 4 cm, so the hypotenuse is twice the short leg.
Recall the property of 30°x60°x90° triangle:
- a : b : c = 1 : √3 : 2, where a- short leg, b- long leg, c- hypotenuse.
It means OC: OA = 1 : 2, so angles AOC and BOC are both 60° as adjacent to short legs.
In order to find the shaded area we need to find the area of sector OADB and subtract the area of triangle OAB.
Area of <u>sector:</u>
- A = π(θ/360)r², where θ- central angle,
- A = π*((mAOC + mBOC)/360)*r²,
- A = π*((60 + 60)/360))(4²) = 16.76 cm².
Area of<u> triangle AO</u>B:
- A = (1/2)*OC*(AC + BC), AC = BC = OC√3 according to the property of 30x60x90 triangle.
- A = (1/2)(2*2√3)*2 = 4√3 = 6.93 cm²
The shaded area is:
- A = 16.76 - 6.93 = 9.83 cm²
Answer: the answer is 150 :)
Step-by-step explanation: Volume of a cone is
V = 1/3 pi * r^2 *h
The volume of one cone is
pi = 3.14
r = d/2 = 6/2 =3
h=9
Substitute what we know
V = 1/3 * (3.14) * (3^2) * (9)
= 27* 3.14
= 84.78 cm^3
The water cooler has 12717 cm^3 water
Divide the water by the volume of the paper cup cone and we will know how many paper cup cones we can fill, assuming we fill them completely.
12717/ 84.78 = 150
We can fill 150 paper cup cones. have a great day!
Let the total amount of pages be t
t=30+1/8t+2/8t
now simplify
t=30+3/8t
5/8t=30
divide 30 by 5
1/8=6
now you know 1/8 of the book is 6 pages which means the whole book has 48 pages.
Ht of ceiling = 10 ft which is two-thirds of living rm ceiling
Ht of living rm ceiling = 2/3x = 10 ft
2/3h = 10 ft
2/3h times 3/2 to solve for h = 10 times 3/2
h = 30/2
h = 15 ft