Answer:
Code is in both c++ and java
Explanation:
C++ Code
#include<iostream>
#include <sstream> // for string streams
#include <string> // for string
using namespace std;
int main()
{
int num;
cout<<"Enter Non-Negative number :";
cin>> num;
// declaring output string stream
ostringstream str1;
// Sending a number as a stream into output
// string
str1 << num;
// the str() coverts number into string
string geek = str1.str();
int count =0;
for (int i = 0; i < geek.size(); i++){
if(geek[i]=='7'){
count++;
}
}
// Displaying the string
cout << "the number of 7s in "<<num<< "is"<<count;
return 0;
}
Java Code
import java.util.Scanner;
public class LuckySeven{
public static void main(String[] args){
Scanner scanner = new Scanner(System.in);
System.out.print("Enter Number :");
int number = scanner.nextInt();
String numberString = number+"";
int count =numberString.length()- numberString.replaceAll("7","").length();
System.out.println("Number of 7's in "+numberString+" are "+count);
}
}
Code Explanation
First we need to take integer number as input from user.
As we need to iterate through all of the digits in number, that's why we need to convert integer to string as string is an array of character so we will iterate through number array and match the total count of 7 on every index.
At the end we will display the total count of 7 in number.
Sample Output
Case 1
Enter Non-Negative number :3482
the number of 7s in 3482 is 0
Case 2
Enter Non-Negative number :372771
the number of 7s in 372771 is 3
, then it will become 16.
then it will become
which will become 16.