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Kazeer [188]
1 year ago
9

What block(s) would most effectively keep a sprite from moving off the screen?

Computers and Technology
1 answer:
Sonja [21]1 year ago
8 0

The block most effectively keep a sprite from moving off the screen if if on edge, bounce. Hence option B is correct.

<h3>What is screen?</h3>

Screen is defined as a portable or stationary object that offers shelter, acts as a partition, etc., and often consists of a covered frame. Screening is defined as the procedure of locating or choosing individuals from a community according to one or more selection criteria.

The block will kept more perfectly if one of the edge there is bounce so that the box will not fall from the sprite.

Thus, the block most effectively keep a sprite from moving off the screen if if on edge, bounce. Hence option B is correct.

To learn more about screen, refer to the link below:

brainly.com/question/23902291

#SPJ1

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Using a loop and indexed addressing, write code that rotates the members of a 32-bit integer array forward one position. The val
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<h2>Answer:</h2><h2></h2>

//begin class definition

public class Rotator{

    //main method to execute the program

    public static void main(String []args){

       

       //create and initialize an array with hypothetical values

       int [] arr =  {10, 20, 30, 40};

       

       //create a new array that will hold the rotated values

       //it should have the same length as the original array

       int [] new_arr = new int[arr.length];

       

       

       //loop through the original array up until the

       //penultimate value which is given by 'arr.length - 1'

      for(int i = 0; i < arr.length - 1; i++ ){

           //at each cycle, put the element of the

           //original array into the new array

           //one index higher than its index in the

           //original array.

          new_arr[i + 1] = arr[i];

       }

       

       //Now put the last element of the original array

       //into the zeroth index of the new array

       new_arr[0] = arr[arr.length - 1];

       

       

       //print out the new array in a nice format

      System.out.print("[ ");

       for(int j = 0; j < new_arr.length;  j++){

           System.out.print(new_arr[j] + " ");

       }

       System.out.print("]");

       

    }

   

   

}

<h2>Sample Output:</h2>

[ 40 10 20 30 ]

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining important parts of the code.  A sample output has also been provided.

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