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Kazeer [188]
1 year ago
9

What block(s) would most effectively keep a sprite from moving off the screen?

Computers and Technology
1 answer:
Sonja [21]1 year ago
8 0

The block most effectively keep a sprite from moving off the screen if if on edge, bounce. Hence option B is correct.

<h3>What is screen?</h3>

Screen is defined as a portable or stationary object that offers shelter, acts as a partition, etc., and often consists of a covered frame. Screening is defined as the procedure of locating or choosing individuals from a community according to one or more selection criteria.

The block will kept more perfectly if one of the edge there is bounce so that the box will not fall from the sprite.

Thus, the block most effectively keep a sprite from moving off the screen if if on edge, bounce. Hence option B is correct.

To learn more about screen, refer to the link below:

brainly.com/question/23902291

#SPJ1

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RSB [31]

Answer:

From Networkopoint of view, a node is a redistribution point or communication point or a connection point.

It can also mean devices or data points on a large network Such as laptop, phones, printers, etc

Explanation:

3 0
3 years ago
What is the name of the mvost powerful battery
sergij07 [2.7K]
Optima battery because it is stronger than a factory battery
6 0
3 years ago
NAME SEARCH In the Chap07 folder of the Student Sample Programs, you will find the following files: GirlNames.txt—This file cont
Tems11 [23]

Answer:

Explanation:

I do not have the files listed in the question so I have made two test files with the same names. This code is written in Python, we are assuming that the names on each file are separated by newlines.

f1 = open("GirlNames.txt", 'r')

f1_names = f1.read()

f1_names_list = f1_names.split('\n')

f2 = open("BoyNames.txt", 'r')

f2_names = f2.read()

f2_names_list = f2_names.split('\n')

print(f1_names_list)

print(f2_names_list)

boy_or_girl = input("Would you like to enter a boy or girl name or both: ").lower()

if boy_or_girl == 'boy':

   name = input("Enter name: ")

   if name in f2_names_list:

       print("Yes " + name + " is in the list of most popular boy names.")

   else:

       print("No, it is not in the list")

elif boy_or_girl == 'girl':

   name = input("Enter name: ")

   if name in f1_names_list:

       print("Yes " + name + " is in the list of most popular girl names.")

   else:

       print("No, it is not in the list")

elif boy_or_girl == 'both':

   girlname = input("Enter Girl name: ")

   if girlname in f1_names_list:

       print("Yes " + girlname + " is in the list of most popular girl names.")

   else:

       print("No, it is not in the list")

   boyname = input("Enter name: ")

   if boyname in f2_names_list:

       print("Yes " + boyname + " is in the list of most popular girl names.")

   else:

       print("No, it is not in the list")

else:

   print("Wrong input.")

4 0
3 years ago
Is recursion ever required to solve a problem? What other approach can you use to solve a problem that is repetitive in nature?
Setler79 [48]

Answer:

No you can not tell that recursion is ever required to solve a problem.

Recursion is required when in the problem, the solution of the input depends on the solution of the subsets of the input.

Iteration is also another form of repetitive approach we follow to solve that kind of problems.

But the difference between recursion and iteration is :

  • In recursion we call the function repeatedly to return the result to next level.
  • In iteration certain bunch of instructions in a loop are executed until certain conditions met.

Explanation:

For example in the Fibonacci sequence problem, to find f_{n}, we need to compute f_{n-1} and f_{n-2} before that.

  • In case of recursion we just call the method Fibonacci(n) repeatedly only changing the parameter Fibonacci(n-1), that calculates the value and return it.

                           Fibonacci(n)

                           1. if(n==0 or n==1)

                           2.       return 1.

                           3.else

                           4.      return( Fibonacci(n-1)+Fibonacci(n-1) )

  • But in case of iteration we run a loop for i=2 to n, within which we add the value of current f_{i-1} and f_{i-2} to find the value of f_{i}

                           Fibonacci(n)

                           1. if(n<=2)

                           2.    result = 1

                           3.     else

                           4. result1 =1 and result2=1.

                           5.      {  result = result1 +result2.

                           6.         result1= result2.

                           7.         result2 = result.

                           8.      }

                           9.  output result.

8 0
3 years ago
Which technology can be used as a defense against dos and ddos syn flood attacks?
Montano1993 [528]
In terms of websites, there's a service called cloud flare which can prevent DDOS attacks in websites. Other applications you would have to look up. Hopefully this helps!
6 0
3 years ago
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