Answer:
because it helps them understand their contributions and obligations towards the organisation.
Explanation:
In an organizational setup, the need for healthy and effective communication among employees and employers is a crucial element for the overall success of the organisation. Healthy and effective communication helps in the productivity of the employees because it helps them understand their contributions and obligations towards the organisation.
Good communication improves the employees' morality and sincerity as it helps them feel responsible and as an important member of the organisation. Hence, strengthening their relationships and, as a result, increasing their productivity and efficiency.
Answer:
1. A) Language of graphics-oriented.
B) Initial public offering
C)
D) Central processing unit
2A) False
B) True
C) False
D) True
Answer:
It's a compact way of doing an if-else statement.
General Format is
<<em>condition</em>> ? <if condition is true> : <else>;
Example:
I could rewrite:
if(a==1) temp = 1;
else temp = 999;
as
temp = (a==1) ? 1 : 999;
Answer:
It can be a really good approach to use a local solver using the min conflicts heuristic in solving sudoku problems. It will work better actually. In this process, the value chosen is the value with the minimum conflicts. This is the general way a normal person would also tackle this problem. By this approach, if we keep taking the values with minimum conflicts the sudoku puzzle can be solved with a better performance.
Explanation:
Answer:
#include <iostream>
using namespace std;
int * reverse(int a[],int n)//function to reverse the array.
{
int i;
for(i=0;i<n/2;i++)
{
int temp=a[i];
a[i]=a[n-i-1];
a[n-i-1]=temp;
}
return a;//return pointer to the array.
}
int main() {
int array[50],* arr,N;//declaring three variables.
cin>>N;//taking input of size..
if(N>50||N<0)//if size greater than 50 or less than 0 then terminating the program..
return 0;
for(int i=0;i<N;i++)
{
cin>>array[i];//prompting array elements..
}
arr=reverse(array,N);//function call.
for(int i=0;i<N;i++)
cout<<arr[i]<<endl;//printing reversed array..
cout<<endl;
return 0;
}
Output:-
5
4 5 6 7 8
8
7
6
5
4
Explanation:
I have created a function reverse which reverses the array and returns pointer to an array.I have also considered edge cases where the function terminates if the value of the N(size) is greater than 50 or less than 0.
