2 years ago

The lines y equals=3x minus−1 and y equals=ax plus+2 are perpendicular if aequals=_______.

1 answer:

3 0

Since perpendicular lines have their slopes as negative reciprocals, the negative reciprocal of the given slope (3) is -1/3. Therefore the a value is -1/3.

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Rewrite the function by completing the square (vertex form)<br><br> f(x)=x^2+16x-46

insens350 [35]

Answer:

$\large\boxed{f(x)=(x+8)^2-110}$

Step-by-step explanation:

$\text{The vertex form of equation}\ y=ax^2+bx+c:\\\\y=a(x-h)^2+k\\\\\text{We have the equation:}\\f(x)=x^2+16x-46=x^2+2(x)(8)-46=x^2+2(x)(8)+8^2-8^2-46\\\\\text{use}\ (a+b)^2=a^2+2ab+b^2\to x^2+2(x)(8)+8^2=(x+8)^2\\\\f(x)=(x+8)^2-64-46=(x+8)^2-110$