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Brilliant_brown [7]
3 years ago
13

Please help me please will give brainliest to anyone who is good ​

Mathematics
1 answer:
Sever21 [200]3 years ago
3 0

Answer:

D

As temperature increases, so does mpg meaning better milage in warmer temperatures

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Find the value of x for which f(x)=-2
enyata [817]

Answer:

x=2

Step-by-step explanation:

6 0
3 years ago
Tax rates are 10% on the first 10,000 you earn and 20% on amounts over that. You earn 15,000. What is your tax?
OleMash [197]
This problem can be divided into two parts Part 1 - income up to $10,000 times 10% = $1,000 Part 2 - income over $10,000 = $15,000 - 10,000 = $5,000then, $5,000 times 20% = $1,000 Finally, $1,000 + 1,000 = $2,000
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3 years ago
Verify that this trigonometric equation is an identity?
Vlada [557]
\cot x\sec^4 x=\cot x+2\tan x+\tan^3x\\\\L=\dfrac{\cos x}{\sin x}\cdot\dfrac{1}{\cos^4x}=\dfrac{1}{\sin x}\cdot\dfrac{1}{\cos^3x}=\dfrac{1}{\sin x\cos^3x}\\\\R=\dfrac{\cos x}{\sin x}+2\cdot\dfrac{\sin x}{\cos x}+\dfrac{\sin^3x}{\cos^3x}\\\\=\dfrac{\cos x\cos^3x}{\sin x\cos^3x}+\dfrac{2\sin x\cos^2x}{\cos x\sin x\cos^2x}+\dfrac{\sin^3x\sin x}{\cos^3x\sin x}\\\\=\dfrac{\cos^4x+2\sin^2x\cos^2x+\sin^4x}{\sin x\cos^3x}\\\\=\dfrac{(\cos^2x)^2+2\sin^2x\cos^2x+(\sin^2x)^2}{\sin x\cos^3x}

=\dfrac{(\cos^2x+\sin^2x)^2}{\sin x\cos^3x}=\dfrac{1}{\sin x\cos^3x}=L\\\\Used:\\\tan(a)=\dfrac{\sin(a)}{\cos(a)}\\\cot(a)=\dfrac{\cos(a)}{\sin(a)}\\\sec(a)=\dfrac{1}{\cos(a)}\\\sin^2a+\cos^2a=1\\(a+b)^2=a^2+2ab+b^2
8 0
3 years ago
Help ASAP can somebody help
pentagon [3]
Hmm I think it’s try b
8 0
3 years ago
Benjamin traveled at an average speed of 65 miles per hour for 4.5 hours and then traveled at an average speed of 70 miles per h
shusha [124]

Answer:

542.5

Step-by-step explanation: tRUST ME ON THIS

4 0
3 years ago
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