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4 years ago

P. The inventory of a store 2 years ago was worth $45,000. This year it is

Mathematics

2 answers:

MariettaO [177]4 years ago

5 0

Answer:10% increase

Step-by-step explanation:

49500-45000=4500

4500/45000=0.1

0.1x100=10

10% increase

Nimfa-mama [501]4 years ago

3 0

Answer:

10%

Step-by-step explanation:

follow the rules of calculating percentages.

fractions, decimals, etc.

pls mark brainliest

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4k to the 2nd power divided by 8k to the 5th power

mr_godi [17]

The answer in fraction form would be 1/2048000000000 in decimal form it is 4.8828125x10 to the power of -13

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3 years ago

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Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n 2 if heads comes up

Artyom0805 [142]

Answer:

In the long run, ou expect to lose $4 per game

Step-by-step explanation:

Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n^2 if heads comes up first on the nth toss.

Assuming X be the toss on which the first head appears.

then the geometric distribution of X is:

X $\sim$ geom(p = 1/2)

the probability function P can be computed as:

$P (X = n) = p(1-p)^{n-1}$

where

n = 1,2,3 ...

If I agree to pay you $n^2 if heads comes up first on the nth toss.

this implies that , you need to be paid $\sum \limits ^{n}_{i=1} n^2 P(X=n)$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = E(X^2)$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =Var (X) + [E(X)]^2$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+(\dfrac{1}{p})^2$ ∵ X $\sim$ geom(p = 1/2)

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+\dfrac{1}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p+1}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-p}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-\dfrac{1}{2}}{(\dfrac{1}{2})^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{4-1}{2} }{{\dfrac{1}{4}}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{3}{2} }{{\dfrac{1}{4}}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ 1.5}{{0.25}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =6$

Given that during the game play, You pay me $10 , the calculated expected loss = $10 - $6

= $4

∴

In the long run, you expect to lose $4 per game

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3 years ago

Find the area of the circle<br> Pls help quick

tigry1 [53]

Answer:

153.86.

Step-by-step explanation:

Formula for area of a circle: A= Pi R (R is radius) squared. First fill in the numbers: 3.14x7^2 Then Solve for the squared: 7^2=49, then finally multiply 49x3.14 which gets you to 153.86.

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3 years ago

How do you interpret the statement that F(60)=86?

igor_vitrenko [27]

Answer:

Step-by-step explanation:

"F" is the name of a function. If we choose "60" as the input to this function, the resulting output vaue is 86. The function F maps 60 (input) onto 86 (output).

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Minchanka [31]

Answer:

Step-by-step explanation:

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