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Alexandra [31]
1 year ago
8

Write the first five terms of the sequence defined by the explicit formula an=-4n(n-1)

Mathematics
1 answer:
vladimir2022 [97]1 year ago
7 0

The explicit formula of the sequence is given by a_n = -4n(n-1).

We have to find the first five terms of the sequence.

The first term:

\begin{gathered} a_1=-4\times(1)(1-1) \\ =-4(0) \\ =0 \end{gathered}

The second term:

\begin{gathered} a_2=-4(2)(2-1) \\ =-8(1) \\ =-8 \end{gathered}

The third sum:

\begin{gathered} a_3=-4(3)(3-1) \\ =-12(2) \\ =-24 \end{gathered}

The fourth term:

\begin{gathered} a_4=-4(4)(4-1) \\ =-16(3) \\ =-48 \end{gathered}

The fifth term:

\begin{gathered} a_5=-4(5)(5-1) \\ =-20(4) \\ =-80 \end{gathered}

Thus, option D is correct.

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<h3>Explain about the concurrency of medians?</h3>

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1 year ago
Sanjay graphs a quadratic function that has x-intercepts of –3 and 7. Which functions could he have graphed?
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we will select each options and find zeros

(a)

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for finding x-intercept , we can set g(x)=0

and then we can solve for x

g(x)=x^2-4x-21=0

now, we can factor it

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we get

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(b)

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we can set it to 0

and then we can solve for x

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we can set it to 0

and then we can solve for x

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(d)

g(x)=-(x+3)(x-7)

now, we can set it to 0

and then we can solve for x

g(x)=-(x+3)(x-7)=0

x=-3,x=7

so, this is TRUE

(e)

we have

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now, we can set it to 0

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