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lukranit [14]
3 years ago
10

-19.5 degrees celcius in 2.4 minutes What is the average temperature per minute the container cooled?

Mathematics
1 answer:
klemol [59]3 years ago
4 0
Idk tbh man I think sumbody else will answer
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Erik spends $680 for cable television service. The cable company offers a deal that promises Erik 3 free months of cable if he s
Alex777 [14]

Answer:

20

Step-by-step explanation:

3 0
3 years ago
What is the greatest common factor of 45x^3, 24x^2, and 16x?
Phoenix [80]

Answer:

\huge\boxed{\sf GCF = x}

Step-by-step explanation:

<u>Firstly we'll factorize the terms:</u>

45x³ = 3 * 3 * 5 * x * x * x

24x² = 2 * 2 * 2 * 3 * x * x

16x = 2 * 2 * 2 * 2 * x

<u>The factor which is common in all three terms is:</u>

= x

Hence GCF = x

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
8 0
3 years ago
76.8 of what is 40.32
bearhunter [10]
Hey there

Lets solve this question together,

Convert 76.8% to a decimal.

0.768 * x=40.32

Multiply 0.768 by x to get 0.768x.

0.768x=40.32

Multiply each term by 1 / 0.768 and simplify.

Cancel the common factor of 0.768.

x=40.32 / 0.768

Divide 40.32 by 0.768 to get 52.5

x=52.5
6 0
3 years ago
What is 674×673×142÷3​
anzhelika [568]

Step-by-step explanation:

674 \times 673 \times 142 \div 3 \\  \\ =  674 \times 673 \times 142  \times  \frac{1}{3}  \\  \\  = 64,411,484\times  \frac{1}{3}   \\  \\  = 21,470,494.7 \\

8 0
4 years ago
The mean yearly rainfall in Sydney, Australia, is about 134 mm and the standard deviation is about 66 mm ("Annual maximums of,"
svetlana [45]

Answer:

At least 202.44 mm in the top 15%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 134, \sigma = 66

How many yearly mm of rainfall would there be in the top 15%?

At least X mm.

X is the 100-15 = 85th percentile, which is X when Z has a pvalue of 0.85. So X when Z = 1.037.

Z = \frac{X - \mu}{\sigma}

1.037 = \frac{X - 134}{66}

X - 134 = 66*1.037

X = 202.44

At least 202.44 mm in the top 15%.

5 0
3 years ago
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