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GuDViN [60]
1 year ago
12

You have a choice between 2 jobs, one pays $8.25/hr but requires you to spend $20 to get a uniform. The other pays $7.50/hr. At

how many hours will the job be equal?
Mathematics
1 answer:
Veronika [31]1 year ago
5 0

Step-by-step explanation + Answer:

x = 1st job

y = 2nd job

x + y = 22......x = 22 - y

7x + 8.25y = 171.50

7(22 - y ) + 8.25y = 171.50

154 - 7y + 8.25y = 171.50

-7y + 8.25y = 171.50 - 154

1.25y = 17.50

y = 17.50 / 1.25

y = 14 <== 14 hrs at the 8.25 per hr job

x + y = 22

x + 14 = 22

x = 22 - 14

x = 8 <=== 8 hrs at the 7 per hr job

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Which of the following coordinates exists on the line y = 3x + 1?
Natalija [7]

We are given

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y=3x+1

we will check each options

option-A:

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1=3*3+1

1=10

we can see that

they are not equal

so, this is FALSE

option-B:

we can plug (-1,-2)

x=-1 and y=-2

-2=3*-1+1

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we can see that

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option-C:

we can plug (-3,4)

x=-3 and y=4

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we can see that

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option-D:

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6=3*2+1

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we can see that

they are not equal

so, this is FALSE


6 0
2 years ago
Read 2 more answers
Write a third degree polynomial function that has real zeros -1, -2 and 4
ra1l [238]

Answer:

f(x) = x^{3}  - x^{2}  -  10x  -8

Step-by-step explanation:

All you have to do is multiply (x + 1)(x + 2)(x - 4)

You should get x^{3}  - x^{2}  -  10x  -8

So,  f(x) = x^{3}  - x^{2}  -  10x  -8

8 0
2 years ago
If x is increased by 20%.<br>then what<br>will be the increased percent if there will be x^2?<br>​
nevsk [136]

Answer:

the area will be increased by 44%

Step-by-step explanation:

5 0
2 years ago
A spherical ball with a volume of 972π in.3 is packaged in a box that is in the shape of a cube. The edge length of the box is e
aivan3 [116]
To find the volume of the box you will use the volume of the sphere formula to find the radius of the circular region of the sphere. You wil then double the radius to find the diameter.

V = 4/3 x pi x r^3
972 x pi= 4/3 x pi x r^3
729 = r^3
The cubic root of 729 is 9 because 9 x 9 x 9 = 729.

The radius is 9 inches, and the diameter is 18 inches.

The volume of the box is 18 in x 18 in x 18 in or 5832 in.³.
4 0
2 years ago
Jackson's rectangular orchard is 6 km long and 4 km wide.    What is the area of Jackson's orchard?
Levart [38]
For a rectangle area, use base x height, or length x width.


6 km long x 4 km wide = 24 km 

The area of Jackson's orchard is 24 km

hope this helps

x = multiply
5 0
3 years ago
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