Answer: the third option
Step-by-step explanation:
Complete question:
A student throws a heavy ball downward off the top of a building with a speed of 18m/s. The ball reaches a speed of 41m/s just before striking the ground. Neglect drag, find the height of the building.
Answer:
The height of the building is 69.235 m
Step-by-step explanation:
Given;
initial velocity of the ball, u = 18 m/s
final velocity of the ball, v = 41 m/s
The height of the building is equal to distance traveled by the ball downward.
Apply the following kinematic equation;
v² = u² + 2gh
where;
g is acceleration due to gravity
h is height of the building
41² = 18² + 2(9.8)h
1681 = 324 + 19.6h
19.6h = 1681 - 324
19.6h = 1357
h = 1357 / 19.6
h = 69.235 m
Therefore, the height of the building is 69.235 m
Boys are a 2:1 ratio to girls.
Hope you have a nice day
0.18 is bigger because it is closer to 1 and 0.8 is closer to 0
Answer:
Below in bold.
Step-by-step explanation:
A. −16x2 + 24x + 16 = 0
-8(2x2 - 3x - 2) = 0
-8(2x + 1 )(x - 2) = 0
x = -0.5, 2.
So the x-intercepts are (-0/5, 0) and (2, 0).
B. As the leading coefficients is negative (-16) the vertex of the graph will be a Maximum.
To find its coordinates we convert the function to vertex form:
f(x) = −16x2 + 24x + 16
= -16(x^2 - 1.5x) + 16
Completing the square on contents of the parentheses:
= -16 [(x - 0.75)^2 - 0.75^2] + 16
= -16(x - 0.75)^2 - 16 * -0.75^2 + 16
= -16(x - 0.75)^2 + 9 + 16
= -16(x - 0.75)^2 + 25.
So the coordinates of the vertex are (0.75, 25)
