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Tatiana [17]
3 years ago
9

Which statement is true about the sides

Mathematics
1 answer:
ivanzaharov [21]3 years ago
4 0
The answer to your question is D
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Please help, I don’t get it
KatRina [158]

Answer:

What do not you understand?

5 0
3 years ago
The length of a rectangle is 2 in longer than its width. if the perimeter of the rectangle is 44 in , find its area.
valkas [14]
P = 2(L + W)
P = 44
L = W + 2

44 = 2(W + 2 + W)
44 = 2(2W + 2)
44 = 4W + 4
44 - 4 = 4W
40 = 4W
40/4 = W
10 = W

L = W + 2
L = 10 + 2
L = 12

A = L * W
L = 12
W = 10

A = 12 * 10
A = 120 square inches <===
7 0
3 years ago
Read 2 more answers
At 7:00pm one evening, the temperature was -8°F. At 6:00am the next morning me
OleMash [197]

Answer:

B mark me brainliest!!!!?

Step-by-step explanation:

It increased 37 F

A) -8-|25| is -8-25 which is -37 it didn’t decrease lol!

B) |-8-25| is |-37| which is 37 which is the answer

C) -37 nope

D) 8-25 is not 37 so the answer is B

4 0
3 years ago
Paola is selling bags of homemade caramel corn for a club fundraiser. The amount she makes depends on the number of bags sold. B
BlackZzzverrR [31]

Answer:

She realised $12 from selling 8 bags of caramel corn

Step-by-step explanation:

Given

(8, 12)

Required

Determine what it means based on the available information

A function is always written as (x,y)

Where x is dependent on y

By comparison,

x = bags of caramel corn = 8

y = amount realised = 12

Assuming the currency is in dollars

Conclusively,

She realised $12 from selling 8 bags of caramel corn.

5 0
3 years ago
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
3 years ago
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