To answer we let x be the amount of money that Sam invested during the first year.
Below are the expressions translated from the given word forms for the amount invested.
Sam:
2nd year : amount = 5x/2 - 2000
3rd year : amount = x/5 + 1000
The sum of money invested by Sam is:
x + (5x/2 - 2000) + (x/5 + 1000)
Similarly, we derive the expressions that we use for the amount that Sally invested.
Sally
1st year : amount = 3x/2 - 1000
2nd year : amount = 2x - 1500
3rd year : amount = x/4 + 1400
The total amount that Sally invested is,
total = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)
Equating the two equations:
(x) + (5x/2 - 2000) + (x/5 + 1000) = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)
Solving for x,
x = 2000
For Sally's investment in the third year:
amount = x/4 + 1400 = (2000/4 + 1400) = 1900
ANSWERS:
Sam's first year = $2000
Sally's third year = $1900
The answer: b><span><span><span>4<span> or </span></span>b</span><<span>−<span>5</span></span></span>
For this case we must solve each of the functions.
We have then:
f (x) = x2 - 9, and g (x) = x - 3
h (x) = (x2 - 9) / (x - 3)
h (x) = ((x-3) (x + 3)) / (x - 3)
h (x) = x + 3
f (x) = x2 - 4x + 3, and g (x) = x - 3
h (x) = (x2 - 4x + 3) / (x - 3)
h (x) = ((x-3) (x-1)) / (x - 3)
h (x) = x-1
f (x) = x2 + 4x - 5, and g (x) = x - 1
h (x) = (x2 + 4x - 5) / (x - 1)
h (x) = ((x + 5) (x-1)) / (x - 1)
h (x) = x + 5
f (x) = x2 - 16, and g (x) = x - 4
h (x) = (x2 - 16) / (x - 4)
h (x) = ((x-4) (x + 4)) / (x - 4)
h (x) = x + 4
Answer:
1
Step-by-step explanation:
Two ordered pairs that can be seen are (0,1) and (1,2)
Using delta y/ delta x,
(2-1)/(1-0) = slope
slope = 1/1
slope = 1
Line 1 is parallel and slope -1.33333 or -4/3
Line 2 is parallel and slope 0.75 or 6/8
Line 3 is parallel and slope 0.75 or -3/-4 i got the answers on Omni calculator
