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Svet_ta [14]
1 year ago
15

You have recently compiled a custom Linux kernel. You notice some performance issues with and need to use the kernel log files t

o troubleshoot the problem. Which command should you use?
Computers and Technology
1 answer:
Alex17521 [72]1 year ago
3 0

The command you should use to view the kernel log files is dmesg. This command prints out the kernel log messages, which can provide useful information in troubleshooting performance issues.

<h3>Troubleshooting Performance Issues Using Linux Kernel Log Files</h3>

The Linux kernel is the core of any Linux-based operating system and is responsible for managing system resources and providing a platform for applications to run. This makes it essential to have a reliable kernel. However, like any complex system, sometimes there are performance issues that need to be troubleshooted. In such cases, kernel log files can help provide valuable insight into the problem.

Kernel log files are the records of the kernel's activities. They provide detailed information about the system, including system errors, warnings, and other important events. This allows for detailed analysis of the system and can help pinpoint the source of any performance issues.

Learn more about systems :

brainly.com/question/14688347

#SPJ4

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What are some of the benefits of project
galina1969 [7]

Answer:

The project is more likely to be finished on  time.

Tasks can be done more efficiently.

Explanation:

Project management refers to the process involved in the management and accomplishment of the project. It includes the process, techniques, and guidance to carry on to complete a project. Project management helps in achieving the desired outcomes of the project. The efficient use of the resources and the proper management of the skills are ensured in project management. Better communication and an increase in satisfaction help in improving productivity.

4 0
3 years ago
. the web is based on the ________ protocol
elena55 [62]
The standard (and default) port for HTTP<span> servers to listen on is 80, though they can use any port. </span>HTTP<span> is based on the </span>TCP/IP protocols<span>, and is used commonly on the Internet for transmitting web-pages from servers to browsers.</span>
3 0
3 years ago
HELP GENIUS Rank :))) DoNT answer If you don't know
RideAnS [48]

An instance in my life where I rendered services was when I worked in a grocery store.

The roles of entrepreneur include:

  • Allocating employees duties.
  • Improving standard of living.
  • Taking risks.

The three challenges that a young entrepreneur faces today include:

  • Financial instability.
  • Conflicts with education.
  • Lack of business skills.

The top three characteristics of an entrepreneur include:

  • Innovation.
  • Confidence
  • Risk taking

<h3>Who's an entrepreneur?</h3>

It should be noted that a entrepreneur is an individual who owns business and take risks.

The roles of entrepreneur include allocating employees duties, improving standard of living, and taking risks

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3 0
1 year ago
Which of the following is the biggest issue facing wireless communication today?
anygoal [31]

Answer:

threats to privacy

Explanation:

7 0
3 years ago
The ArrayList class contains a trim method that resizes the internal array to exactly the capacity. The trim method is intended
andreev551 [17]

Answer:

public void trimToSize() {

modCount++;

if (size < elementData.length) {

elementData = (size == 0)

? EMPTY_ELEMENTDATA

: Arrays.copyOf(elementData, size);

}

}

Now, the running time for copyOf() function is O(N) where N is the size/capacity of the ArrayList. Hence, the time complexity of trimToSize() function is O(N).

Hence, the running time of building an N-item ArrayList is O(N^2).

Please find the sample code below.

CODE

==================

import java.util.ArrayList;

public class Driver {

  public static void main(String[] args) throws Exception{

      int N = 100000;

      ArrayList<Integer> arr = new ArrayList<>(N);

     

      long startTime = System.currentTimeMillis();

      for(int i=0; i<N; i++) {

          arr.add(i);

          arr.trimToSize();

      }

      long endTime = System.currentTimeMillis();

      double time = (endTime - startTime)/1000;

      System.out.println("Total time taken = " + time + " seconds.");

  }

}

Explanation:

5 0
3 years ago
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