A terminology which best describe Kevin's goal in terms of expansion and contraction as needs change is: A. Scalability.
<h3>What is scalability?</h3>
Scalability can be defined as a measure of the ability of a system to change (expansion or contraction) in performance and cost as a result of changes in demands of application and system processing, especially in a network architecture.
In this context, we can logically deduce that a terminology which best describe Kevin's goal in terms of expansion and contraction as needs change is scalability.
Read more on scalability here: brainly.com/question/14301721
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Complete Question:
Kevin would like to ensure that his software runs on a platform that is able to expand and contract as needs change. Which one of the following terms best describes his goal? A. Scalability B. Elasticity C. Cost effectiveness D. Agility
Well theirs less travel. Its alot easier. To work from home.
But this is what it said on a website
Most of them figure they can use conference call time to get 'real work' done, chat, read the newspaper.
Answer:
hope you like it
Explanation:
Writing an outline can take place at any time during the writing process. Although it is most commonly used before beginning to write or doing research, this process can also take place during or after writing your paper to make sure your points are organized and make sense.
An outline is a first step for writing: a general, unfinished plan that you will use as a guideline in writing, not a finished product ready to publish. You should use it when you prepare to write a rough draft, before you started writing.
A company violating its terms of service by selling their user’s info is a violation of Digital Privacy
Answer:
Explanation:
The following code is written in Python and is a recursive function as requested that uses the current value of p (which is count in this instance) and raises 2 to the power of p. If the result is greater than or equal to the value of n then it returns the value of p (count) otherwise it raises it by 1 and calls the function again.
def next_pow2(n, count = 0):
if (2**count) < n:
count += 1
return next_pow2(n, count)
else:
return count
