Answer:
-(33+110z)/10z
Step-by-step explanation:
(-7/2z +4)+(1/5z -15)
from BODMAS, solving the one in the bracket
First(-7/2z +4)+(1/5z -15)
Find the Lcm
[-7/2z +4] +[1/5z -15]
(7+8z)/2z +(1-75z)/5z
find the Lcm which is 10z
[5(-7+8z) + 2(1-75z)]/10z
[(-35+40z)+(2-150z)]10z
(-35+2+40z-150z)/10z
(-33-110z)/10z
-(33+110z)/10z
Answer:
10.4
Step-by-step explanation:
For this case we have a function of the form
Where:

We must find the value of the function when the variable x is -5.
Then, substituting, 

We have that by sign law

Answer:

9514 1404 393
Answer:
15 squre units
Step-by-step explanation:
The area of the rectangle is the product of its length and width. The length is AB = 5 units; the width is BC = 3 units. Then the area is ...
A = LW
A = (5 units)(3 units) = 15 units²
The area of rectangle ABCD is 15 square units.
Answer:A
Step-by-step explanation: In exponents,
a
1
m
=
m
√
a
Hence
x
1
2
=
2
√
x