Question

In triangle ABC, find B, to the nearest degree, given a=7, b=10, and C is a right angle.

Answer 1

Answer:

Option D is correct i.e angle B is 55°

Step-by-step explanation:

Given In triangle ABC,  a=7, b=10 and angle C is a right angle.

we have to find the angle B.

As given triangle is right angled triangle,

∴ we can apply the formula of trigonometric ratios to find the angle B

$tanB=\frac{AC}{CB}=\frac{10}{7}$

⇒ $B=tan^{-1}(\frac{10}{7})=0.96 radian=55.0079^{\circ}\sim55^{\circ}$

Hence, angle B is 55°

Option D is correct.