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Verdich [7]
1 year ago
6

a game where two players each throw two dice each. if any one die matches the other, you win a dollar. if there is no match, you

lose a dollar. would you play this game or not and why?
Mathematics
1 answer:
nadezda [96]1 year ago
5 0

Yes, I would play the game, because the probability of winning is 13/18.

Probability:

Probability refer the possible occurrence of any particular event.

Given,

A game where two players each throw two dice each. if any one die matches the other, you win a dollar. if there is no match, you lose a dollar.

Here we need to find whether we able to play this one or not.

To find that one, first, we have to identify the winning scenarios,

Let us consider five winning scenarios. Lets represent the dice outcomes as A, B, C, and D, where your dice are A and B and the other player's are C and D. The five scenarios are:

1) A = B

2) A = C

3) A = D

4) B = C

5) B = D

We know that the total possible outcomes is 6^4. We can go through each scenario and count the possible outcomes. We must be careful to avoid overcounting.

Based on this,

The probability that none match is

=> 6*5*4*3/6^4

=> 360 / 1296

=> 5 / 18

So, probability of winning is,

=> 1 - 5/18

=> 13/18.

So, based on the probability the chance of winning is high. So, we can play it.

To know more about Probability here.

brainly.com/question/11234923

#SPJ4

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A DVD box set includes 3 thriller movies and 2 comidies. Use t to represent the cost of each thriller and c to represent the cos
suter [353]

Answer:

The expression representing the Total cost of 6 boxes is 6(3t + 2c).

The Simplified expression representing the Total cost of 6 boxes is 18t + 12c.

Step-by-step explanation:

Given:

Number of thriller movies = 3

Number of Comedy movies = 2

Let the cost of thriller movie be t

Also Let the cost of comedy movie be c

Total Number of boxes = 6

Now, given a DVD box set includes 3 thriller movies and 2 comedies.

Cost of Each box = 3t + 2c

We need to find the total cost of 6 boxes

Total Cost of 6 boxes is = 6(3t + 2c)

Hence the expression representing the Total cost of 6 boxes is 6(3t + 2c).

Simplifying the above expression we get;

Total Cost of 6 boxes is = 6(3t + 2c)= 6\times3t+6\times2c=18t+12c

Hence the Simplified expression representing the Total cost of 6 boxes is 18t + 12c.

3 0
3 years ago
How do i find LM? On number 2 .
Masja [62]
Given: KL is a tangent to the circle.
LM is another tangent to the circle.

We can use the tangent meeting at an external point theorem.
<em>Theorem</em>: <em>The tangent segments to a circle from an external point are equal.
</em>
Thus, we can say KL = LM, as they lie on a common circle, and are tangents to such circle.

4x - 2 = 3x + 3
4x - 3x = 3 + 2
x = 5

Since LM is 3x + 3, we can substitute the value of x to LM to render:
3(5) + 3 = 18

Thus, LM = KL = 18 units.
4 0
3 years ago
Andy has two similar conical hats, Hat A and Hat B. The diameter of Hat A is 18 inches, and the diameter of Hat B is 9 inches.
valkas [14]
The answer is 2:1 because at first your ratio would be 18:9 but if you divide that by 9 (for simplifying purposes) than its 2:1
5 0
3 years ago
How to solve 3 variable systems
AVprozaik [17]
<span>Pick two pairs: 4x - 3y + z = - 10. 2x + y + 3z = 0. ... Eliminate the same variable from each system: 4x - 3y + z = - 10. 2x + y + 3z = 0. ... Solve the system of the two new equations: -5y - 5z = - 10. 5y - 7z = 34. ... Substitute into one of the original equations: - x + 2y - 5z = 17. ... <span>Check: Does 2(1) + 4 + 3(- 2) = 0 ? Yes.</span></span>
4 0
3 years ago
Find the perimeter of the triangle to the nearest whole unit.<br> 18.<br> 16.<br> 14.<br> 12.
devlian [24]

Answer:

14

Step-by-step explanation:

Perimeter of the ∆ = sum of the length of the 3 sides.

The length of the 3 sides can be calculated by using the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}, to find the distance between the vertices of the ∆.

The coordinates of the 3 vertices are:

(-1, 3), (2, 2), (-2, -2)

Distance between (-1, 3) and (2, 2):

Let,

(-1, 3) = (x_1, y_1)

(2, 2) = (x_2, y_2)

d = \sqrt{(2 -(-1))^2 + (2 - 3)^2}

d = \sqrt{(3)^2 + (-1)^2}

d = \sqrt{9 + 1} = \sqrt{10} = 3.2 units

Distance between (2, 2) and (-2, -2)

Let,

(2, 2) = (x_1, y_1)

(-2, -2) = (x_2, y_2)

d = \sqrt{(-2 - 2)^2 + (-2 - 2)^2}

d = \sqrt{(-4)^2 + (-4)^2}

d = \sqrt{16 + 16} = \sqrt{32} = 5.7 units

Distance between (-2, -2) and (-1, 3)

Let,

(-2, -2) = (x_1, y_1)

(-1, 3) = (x_2, y_2)

d = \sqrt{(-1 -(-2))^2 + (3 -(-2))^2}

d = \sqrt{(1)^2 + (5)^2}

d = \sqrt{1 + 25} = \sqrt{26} = 5.1 units

Perimeter of triangle = 3.2 + 5.7 + 5.1 = 14.0 units

8 0
3 years ago
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