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3 years ago

To make a batch of

1 answer:

7 0

Steve wants to make 2+3/4 batches=2*4/4+3/4=11/4. He needs 2+2/3 cups=2*3/3+2/3=8/3. 11/4*8/3=88/12. You can see both have a factor 2, so 88/12=44/6 and again 44/6=22/3. 22 cannot be devided by 3 but division with rest gives 22/3 = 7 + 1/3.

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Solve x - y = 5 for y

olga55 [171]

X - y = 5
x = y + 5
y = x - 5

6 0

2 years ago

WILL GIVE YOU BRAINLIEST!! (only answer if u know for sure) A coin is flipped 20 times. 13 times the coin lands on heads. What i

tangare [24]

there is a 50% chance of landing on either heads or tails

3 0

3 years ago

Can someone help with this ??

Zigmanuir [339]

I’m sorry but I can’t see the photo so can you tape it out so I can furthermore assist you

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3 years ago

Every year, the students at a school are given a musical aptitude test that rates them from 0 (no musical aptitude) to 5 (high m

morpeh [17]

The question is incomplete. Here is the complete question.

Every year, the students at a school are given a musical aptitude test that rates them from 0 (no musical aptitude) to 5 (high musical aptitude). This year's results were shown in the figure below.

The average (mean) aptitude score:

The median aptitude score:

Answer: mean: 2.73

median: 3

Step-by-step explanation: Mean is the average number of a set of numbers.

The table below shows a frequency of students to each score of the test. To calculate mean with a frequency table, do the following:

$mean=\frac{\Sigma (score*frequency)}{\Sigma frequency}$

$mean=\frac{0*1+1*5+2*0+3*3+4*3+5*3}{1+5+0+3+3+3}$

mean = 2.73

Median is the middle term of a set of data.

When there is a frequency table, median is calculated as:

1) First, determine the total number of observations (n).

For this table, n = 15

2) Because n is odd, find the position of the median using:

$position=\frac{n+1}{2}$

position = 8th

3) The median will be in the 8th position. To find the position, we add the frequencies and in doing so, we notice the position we want is in the score 3 category. So, the median for this frequency table is 3.

Average score of a musical aptitude test is 2.73 and median is 3

8 0

2 years ago

!! AP CALCULUS AB !! find the limit of [(secx*sinx) + (cscx*cosx)]/(3secx) as x approaches 3pi/2

uysha [10]

$f(x)= \frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}}$

$\frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}} \implies \\ \frac{\sin^2{x}+\cos^2{x}}{\sin{x}\cos{x}}\frac{\cos{x}}{3}\implies \\\frac{1}{\sin{x}\cos{x}}*\frac{\cos{x}}{3}\implies \\ \frac{1}{3\sin{x}}$

So,

$\lim_{x \rightarrow \frac{3\pi}{2}}{f(x)=f(\frac{3\pi}{2})=\frac{1}{3\sin{\frac{3\pi}{2}}}=-\frac{1}{3}$

6 0

3 years ago