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DanielleElmas [232]
2 years ago
8

Find the measure of each missing angle in the following kite.

Mathematics
1 answer:
Helga [31]2 years ago
5 0

The measures of the missing angles in the kite are given as follows:

  • Angle A: 116.5º.
  • Angle B: 109º.
  • Angle C: 69.5º.

<h3>How to obtain the angle measures?</h3>

The sum of the internal angle measures of a polygon of n sides is given by the equation presented as follows:

S = (n - 2) x 180º.

The kite, as shown by the image at the end of the answer, has 4 sides, hence the sum of the measures is given as follows:

S = (4 - 2) x 180º

S = 2 x 180º

S = 360º.

Angles B and D are on the opposite side of the kite, as shown by the image at the end of the answer, hence they are congruent and:

B = 109º.

Adding the measures, the value of x is obtained as follows:

5x + 14 + 109 + 3x + 8 + 109 = 360

8x = 164

x = 20.5.

Hence the measures are given as follows:

  • Angle A: 5(20.5) + 14 = 116.5º.
  • Angle C: 3(20.5) + 8 = 69.5º.

<h3>Missing Information</h3>

The model of the kite, with different angle measures, is given by the image at the end of the answer.

More can be learned about the internal angles of a polygon at brainly.com/question/224658

#SPJ1

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kicyunya [14]

Answer:

(a) The probability that fewer than 3 components will fail is  0.8392.

(b) The mean likely number of failures is 1.44.

Step-by-step explanation:

We are given that a complicated mechanical system contains 8 components. If there is an 18% chance that each component will fail during processing, and components fail independently of each other.

Let X = <u><em>Number of components fail during processing</em></u>

The above situation can be represented through the binomial distribution;

P(X=r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ;x=0,1,2,.....

where, n = number of samples (trials) taken = 8 components

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           p = probability of success which in our question is the probability

                 that each component will fail during processing, i.e. p = 18%

SO, X ~ Binom(n = 8, p = 0.18)

(a) The probability that fewer than 3 components will fail is given by = P(X < 3)

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

= \binom{8}{0}\times 0.18^{0} \times (1-0.18)^{8-0}+ \binom{8}{1}\times 0.18^{1} \times (1-0.18)^{8-1}+ \binom{8}{2}\times 0.18^{2} \times (1-0.18)^{8-2}

= 1 \times 1 \times 0.82^{8}+ 8 \times 0.18^{1}  \times 0.82^{7}+28 \times 0.18^{2}  \times 0.82^{6}

= <u>0.8392</u>

(b) The mean likely number of failures is given by the following formula;

      Mean of X, E(X) = n \times p

                                 = 8 \times 0.18 = 1.44

Hence, the mean likely number of failures is 1.44.

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<u>2.2</u>

Question:

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