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Eva8 [605]
2 years ago
7

Darpana solved the equation s = StartFraction a + b + c Over 3 EndFraction for a. Her steps are shown below: 1. Multiply by 3: s

= StartFraction a + b + c Over 3 EndFraction. 3 s = a + b + c. 2. Subtract b: 3 s minus b = a + b + c minus b. 3 s minus b = a + c. 3. Divide by c: StartFraction 3 s minus b Over c EndFraction = a. Which statement about Darpana's work is true? In step 1 she needed to divide by 3 rather than multiply. In step 2 she needed to add b rather than subtract. In step 3 she needed to subtract c rather than divide. Darpana solved the equation correctly.
Mathematics
2 answers:
snow_lady [41]2 years ago
7 0

Answer:

the correct answer is c

Step-by-step explanation:

Harman [31]2 years ago
5 0

Answer:

Option (c) is correct.

Step-by-step explanation:

Given equation is :

s=\dfrac{a+b+c}{3}

The equation can be solved for a as follows :

Step 1.

Cross multiply the given equation

3s=a+b+c

Step 2.

Now subtract b on both sides

3s-b = a+b+c-b

3s-b = a+c

Step 3.

Subtract c on both sides

3s-b-c=a+c-c

⇒ a=3s-b-c

The statement that is true for Darpana is " In step 3, she needed to subtract c rather than divide".

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It's raining outside, and after 1 hour of rain, the water level in Jake's pond is 2 meters. After 3 hours, the water level is 2.
alexira [117]

Answer: 0.4 meters per hour.

Step-by-step explanation:

The rate of change of distance with respect to time is known as speed.

Formula :\text{Rate of change}=\dfrac{\text{Change in position}}{\text{Change in time}}

Given : It's raining outside, and after 1 hour of rain, the water level in Jake's pond is 2 meters. After 3 hours, the water level is 2.8 meters.

i.e. Change in position= 2.8-2=0.8 meters

Change in time = 3-1=2 hours

i.e. \text{Rate of change}=\dfrac{0.8}{2}=0.4

Hence, the rate of change =0.4 meters per hour.

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NemiM [27]

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3 years ago
Jeannie is an experienced business traveler, often traveling back and forth from San Francisco to the East Coast several times p
lesya692 [45]

Answer:

The probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour is 0.0026.

Jeannie should leave her office 55 minutes early.

Step-by-step explanation:

Let <em>X</em> = time it requires Jeannie to catch her plane.

The random variable <em>X</em> is normally distributed, N(46, 5).

Compute the probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour as follows:

P(X>60)=P(\frac{X-\mu}{\sigma} >\frac{60-46}{5} )\\=P(Z>2.8)\\=1-P(Z

The probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour is 0.0026.

Now, it is provided that Jeannie has 96% chance of catching her flight if she reaches under <em>x</em> minutes.

That is, P (X < x) = 0.96.

Compute the value of <em>x</em> as follows:

P(X

**Use the <em>z</em>-table to compute the value of <em>z</em>.

The value of <em>z</em> is 1.751.

Compute the value of <em>x</em> as follows:

z=\frac{x-46}{5}\\ 1.751=\frac{x-46}{5}\\x=46+(1.751\times5)\\=54.755\\\approx 55

Thus, Jeannie should leave her office 55 minutes early.

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3 years ago
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