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Volgvan
3 years ago
9

For a particular type of motion, the velocity is zero but the speed is a nonzero quantity. Which statement can you make about th

is motion?. . Select one of the options below as your answer:. . . . A. . The starting and ending points of the motion are the same.. . . . . B. . It is a circular motion.. . . . . C. . It is an oscillatory motion.. . . . . D. . The motion occurs in a straight line.
Mathematics
2 answers:
stira [4]3 years ago
6 0
The correct answer for this question is letter A. If the starting and ending points of the motion are the same, velocity is zero but speed is a non-zero quantity. Velocity is a physical vector quantity that requires both magnitude and direction.
zhannawk [14.2K]3 years ago
3 0

Keep in mind this relationship

1.  Relationship between Speed, Distance and time

→Distance = Speed × Time

Speed=\frac{Distance}{Time}

2. Relationship between Displacement, Velocity and time

→Displacement = Velocity × Time

Velocity=\frac{Displacement}{Time}

So, velocity is zero only when

Displacement= 0,so when motion is circular motion,

Total Displacement =0 because initial and final position are same.

But , Speed is not zero, because

Total Distance Traveled = 2 π × (Radius of circle).

So, Option (A)The Starting and end point are same  .. . . . in which  the velocity is zero but the speed is a nonzero quantity.




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Answer:

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Step-by-step explanation:

An equation in the vertex form is written as

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For an equation in the form ax ^ 2 + bx + c the x coordinate of the vertex is defined as

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The point (0, -1) belongs to the function. Thus.

-1 = a(0 + \frac{1}{2}) ^ 2 -\frac{13}{4}

-1 = a(\frac{1}{4}) -\frac{13}{4}\\\\a = \frac{-1 +\frac{13}{4}}{\frac{1}{4}}\\\\a = 9

<em>Then the written function in the form of vertice is</em>

y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

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