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skad [1K]
1 year ago
11

Please help! math question for college algebra mth 107!

Mathematics
1 answer:
kherson [118]1 year ago
8 0

Answer:

Local Minimum: (-2.5, -2), (0, -2)

Local Maximum: (1, 2)

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Minimize embedded content
rjkz [21]

Answer:

84 cm²

Step-by-step explanation:

Surface area of the polyhedron = the sum of the areas of each parts of the net = area of 2 triangles + area of each of the 3 rectangles

Area of 2 triangles:

Base = 4 cm

Height = 3 cm

Area of the 2 triangles = 2(½*base*height)

= 2(½*4*3) = 4*3 = 12 cm²

Area of rectangle with the following dimensions:

Length = 6 cm

Width = 4 cm

Area = length * width = 24 cm²

Area of rectangle with the following dimensions:

Length = 6 cm

Width = 5 cm

Area = length * width = 30 cm²

Area of rectangle with the following dimensions:

Length = 6 cm

Width = 3 cm

Area = length * width = 18 cm²

Surface area of the polyhedron = 12 + 24 + 30 + 18 = 84 cm²

5 0
3 years ago
(03.05 MC) EXPLAIN PLZ
docker41 [41]

Answer:

I think the answer is B.

Step-by-step explanation:

I am very sorry if it is incorrect.

4 0
2 years ago
Read 2 more answers
Find the following trigonometry values <br> cos (150*) = ? <br> sin (150*) = ?
melisa1 [442]

Answer:

See below in bold.

Step-by-step explanation:

cos 150 = - cos(180 - 150)

= - cos 30

= -√3/2.

sin 150

= sin (180 - 150

= sin 30

= 1/2.

4 0
3 years ago
Read 2 more answers
A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d
Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

  • force = 4lb
  • direction = 4, -2
  • displacement = 7ft
  • direction = (0, 4) to (5,1)

The unit vector of the force is

\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}

\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }

The net force acting on the object is

F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}

\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }

The net displacement will be

7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}

The work done will be F.d

w = f. d \\

w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0
2 years ago
Megan and her little sister, Nora, counted their Halloween candy after trick-or-treating. They love taffy and wanted to know who
storchak [24]

Answer:

Nora

Step-by-step explanation:

M 20 : 50 = 2/5

N 11/25

2/5 = 10/25 < 11/25

3 0
3 years ago
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