Answer:
#carry on learning
mark me as brainliest
Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
By:
I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
It’s B.
If I’m wrong them uhh.. my bad?
Answer:
140
Step-by-step explanation:
<u>As per picture:</u>
∠PTQ and ∠RTS are vertical angles and they are equal
- ∠PTQ = (x + 28)°
- ∠RTS = (2x + 16)°
- ∠PTQ = ∠RTS
- x + 28 = 2x + 16
- 2x - x = 28 - 16
- x = 12
∠PTR is supplementary with ∠PTQ and their sum is 180°
- ∠PTQ = 12 + 28 = 40°
- ∠PTR = 180 - 40 = 140°
Answer:
it's not English, sorry I can't help.
Divide 720,000 by 3.
Your answer is 240,000.
