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Ahat [919]
3 years ago
14

Find the coordinates of the midpoint of the segment whose endpoints are H(8, 2) and K(6,10).

Mathematics
1 answer:
katovenus [111]3 years ago
3 0

Answer:

Step-by-step explanation:

(8+6)/2= 14/2 = 7

(2+10)/2 12/2 = 6

(7,6)

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What is the area of the parallelogram below if b=6.1? Round your answer to the nearest tenth.
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The answer to this is 48.8
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What is the perimeter of a rhombus whose diagonals measure 42cm and 56cm?
Trava [24]

Answer:

676

Step-by-step explanation:

d1×d2/2

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3 0
3 years ago
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7 out of 28 is what percent?
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Here's what I did and I checked it So it is correct!!

\frac{7}{28} = \frac{1}{4}

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25% is your answer.

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6 0
3 years ago
The common ratio of a geometric series is 3 and the sum of the first 8 terms is 3280.
Pavlova-9 [17]

Answer:

The first term of the geometric series is 1

Step-by-step explanation:

In this question, we are tasked with calculating the first term of a geometric series, given the common ratio, and the sum of the first 8 terms.

Mathematically, the sum of terms in a geometric series can be calculated as;

S = a(r^n-1)/( r-1)

where a is the first term that we are looking for

r is the common ratio which is 3 according to the question

n is the number of terms which is 8

S is the sum of the number of terms which is 3280 according to the question

Plugging these values, we have

3280 = a(3^8 -1)/(3-1)

3280 = a( 6561-1)/2

3280 = a(6560)/2

3280 = 3280a

a = 3280/3280

a = 1

6 0
3 years ago
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