Here we might have to find p(v intersection w) and for that we use the following formula
p(v U w) = p(v)+p(w)-p(v intersection w)
And it is given that p(v) =01.3 , p(w) = 0.04 and p(v U w ) = 0.14 .
Substituting these values in the formula, we will get
0.14 = 0.13 +0.04 -p(v intersection w)
p(v intersection w) =0.13 +0.04 -0.14 = 0.03
So the required answer of the given question is 0.03 .
Answer: x=12
Step-by-step explanation:
OQ is equal to NL since both contain 90 degree angles and are intersected by a radius. Since OS is 3x-2 and NL is 32, then we need to find OQ and set it equal to NL. OS is half of OQ, so multiplying OS by 2 will get you OQ. 6x-4=32
That yields x=12.
Answer:
y = cos(x) -1
Step-by-step explanation:
The function has a maximum at x=0, a peak-to-peak amplitude of 2, and a period of 2π. It matches a cosine function that has been shifted down 1 unit.
y = cos(x) -1
Answer:
1.27388535028
Step-by-step explanation:
Simply using the formulas