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MatroZZZ [7]
1 year ago
13

Vivian approximated the value of the cube root of 1010 to be 10.0. William claimed that 10.1 is a closer approximation. Whose ap

proximation, Vivian’s or William’s, is closer to the cube root of 1010. Explain your reasoning.
Mathematics
1 answer:
Luda [366]1 year ago
6 0

ANSWER

10.0 ------- Vivian is correct

EXPLANATION

Firstly, find the cube root of 1010

\sqrt[3]{1010\text{ }}\text{ = 10.033}

In the above calculation, the cube root of 1010 is 10.003

The correct approximation of the above value is 10.0. This is because the hundredth value is not upto 5

Recall, figures from 1 - 4 are rounded to zero and figures from 5- 9 are rounded up to 1

since 3 is not upto 5, so it is rounded down to zero

Therefore, Vivian is correct

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Answer:

solution set is (x,y) = (7,6)

Step-by-step explanation:

solving by substitution method

2x +y=20--------------1

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2x+y=20

y= 20-2x------equation 3

adding value of y in equation 2

6x-5y=12

6x-5(20-2x)=12

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16x= 12+100

16x= 112

x= 112/16

x=7

adding value of x in equation 3

y= 20-2x

y= 20- 2(7)

y=20-14

y=6

so solution set (x,y) = (7,6)

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I am Lyosha [343]

Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75

Solution:

Let f be the bags of flour and b be the pounds of butter.

Cost of 20 bags of flour 16 pound of butter = 110

⇒ 20f + 16b = 110 -------------------- (1)

Cost of 30 bags of flour 12 pound of butter = 120

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Equation (1) and (2) are the system of equations.

(2) ⇒ 30f + 12b = 120

Subtract 30f from both sides.

⇒ 12b = 120 – 30f

Divide by 12 on both sides.

$\Rightarrow b =\frac{120-30f}{12}  -------------------- (3)

Substitute (3) in (1).

$20f+16\left(\frac{120-30f}{12}\right)=110

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Divide by –20, we get

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f = 2.50

Substitute f = 2.5 in equation (3), we get

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$b=\frac{15}{4}

b = 3.75

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