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s344n2d4d5 [400]
3 years ago
11

What is the equation for the graph shown?

Mathematics
1 answer:
ELEN [110]3 years ago
6 0
Your answer is c
Hope this helps :)
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Two students went to the schools clinic with fevers Isabell had a temperature of 103.78 and Bryan had a temperature that was 2.3
jeyben [28]

Answer:

1)  The temperature of Bryan  is 101.39°

Step-by-step explanation:

Here, the Temperature of Isabell is given =   103.78 degrees

Now, the temperature  of Bryan = Iaabell's Tempt.  - 2.36

So, temperature  of Bryan  =   (103.78  - 2.36)  degrees

                                              =  101.4  degree

Hence, the temperature of Bryan =    101.4  degree

So, the most appropriate option is 101.39°

4 0
2 years ago
Which of the following could be the graph of y = –xn where n is odd?
mina [271]

Answer:

Step-by-step explanation:

I think you meant y = -x^n, where ^ denotes exponentiation.

If n is odd, the graph begins in Quadrant II and decreases through the origin into Quadrant IV.  This is true of -x, -x^3, -x^5, and so on.

8 0
3 years ago
Please answer this correctly
r-ruslan [8.4K]

Answer:

40 - 59 ⇒ 6

60 - 79 ⇒ 5

3 0
2 years ago
Read 2 more answers
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
2 years ago
(Please answer! :) )
Anna [14]

Answer:

ok

Step-by-step explanation:

6 0
1 year ago
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