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jeka94
3 years ago
6

Which represents the solution set of the inequality 2.9(x+8)<26.1

Mathematics
2 answers:
harina [27]3 years ago
5 0

First you had to multiply by ten from both sides of equation form.

2.9(x+8)*10

Then refine by simplify.

29(x+8)

Next, you divide by twenty-nine from both sides of equation form.

\frac{29(x+8)}{29}< \frac{261}{29}

Simplify.

x+8

Then you subtract by eight from both sides of equation form.

x+8-8

Finally, simplify by equation.

9-8=1

x

Final answer: \boxed{x

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

alukav5142 [94]3 years ago
4 0
The answer is x is less than 1.

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The selling price of an item is 720 it is marked down 30% but the sale price is still marked up from the cost of 420 find the ma
aliya0001 [1]

Answer:

$84

Step-by-step explanation:

720x30=21600

21600/100=216

216=markdown (as a number instead of a percentage)

Now subtract that like this

720-216=504

504= sale price

Then do this

504-420=84

<em><u>Therefore it is $84</u></em>

<em><u /></em>

<em>Hope you understand!</em>

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3 years ago
When Earth is tilted towards the Sun we receive BLANK Sun rays<br> A. Direct<br> B. Indirect
Stella [2.4K]

Answer: i think A. Direct

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3 years ago
Write y+2=13x in standard form.
Afina-wow [57]
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7 0
3 years ago
A random sample of 49 lunch customers was taken at a restaurant. The average amount of time the customers in the sample stayed i
Hunter-Best [27]

Answer:

a)  σ/√n= 1.43 min

c) Margin of error 2.8028min

d) [30.1972; 35.8028]min

e) n=62 customers

Step-by-step explanation:

Hello!

The variable of interest is

X: Time a customer stays at a restaurant. (min)

A sample of 49 lunch customers was taken at a restaurant obtaining

X[bar]= 33 mi

The population standard deviation is known to be δ= 10min

a) and b)

There is no information about the distribution of the population, but we know that if the sample is large enough, n≥30, we can apply the central limit theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;σ²/n)

Where μ is the population mean and σ²/n is the population variance of the sampling distribution.

The standard deviation of the mean is the square root of its variance:

√(σ²/n)= σ/√n= 10/√49= 10/7= 1.428≅ 1.43min

c)

The CI for the population mean has the general structure "Point estimator" ± "Margin of error"

Considering that we approximated the sampling distribution to normal and the standard deviation is known, the statistic to use to estimate the population mean is Z= (X[bar]-μ)/(σ/√n)≈N(0;1)

The formula for the interval is:

[X[bar]±Z_{1-\alpha /2}*(σ/√n)]

The margin of error of the 95% interval is:

Z_{1-\alpha /2}= Z_{1-0.025}= Z_{0.975}= 1.96

d= Z_{1-\alpha /2}*(σ/√n)= 1.96* 1.43= 2.8028

d)

[X[bar]±Z_{1-\alpha /2}*(σ/√n)]

[33±2.8028]

[30.1972; 35.8028]min

Using a confidence level of 95% you'd expect that the interval [30.1972; 35.8028]min contains the true average of time the customers spend at the restaurant.

e)

Considering the margin of error d=2.5min and the confidence level 95% you have to calculate the corresponding sample size to estimate the population mean. To do so you have to clear the value of n from the expression:

d= Z_{1-\alpha /2}*(σ/√n)

\frac{d}{Z_{1-\alpha /2}}= σ/√n

√n*(\frac{d}{Z_{1-\alpha /2}})= σ

√n= σ* (\frac{Z_{1-\alpha /2}}{d})

n=( σ* (\frac{Z_{1-\alpha /2}}{d}))²

n= (10*\frac{1.96}{2.5})²= 61.47≅ 62 customers

I hope this helps!

3 0
3 years ago
Note: angles not necessarily drawn to scale.
Gala2k [10]

Angle AGD is a right angle which equals 90 degrees.

Angle FGD would be 90-73 = 17 degrees.

Angle X is a vertical angle to FGD, which means they are the same.

Angle X = 17 degrees.

3 0
3 years ago
Read 2 more answers
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