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nasty-shy [4]
1 year ago
13

If you select one card at random from a standard deck of 52 cards, what is the probability that the card is a five AND a club?

Mathematics
1 answer:
horsena [70]1 year ago
4 0

Probability is expressed as

number of favorable outcomes/number of total outcomes

The number of cards in a deck is 52(total outcomes)

Recall, there is only 1 five of clubs in a deck of cards(favorable outcomes)

Thus, the probability that the card is a five AND a club is 1/52

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What’s the 5th term is 2,14,98
iragen [17]

\bold{\huge{\orange{\underline{ Solution }}}}

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

  • \sf{ 2 , 14 ,.... 98 }
  • <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

  • \sf{a1\: or \:1st\: term = 2 }
  • \sf{a2 \:or \:2nd\: term = 14 }
  • \sf{an \:or\: last\: term = 98}

<u>Here</u><u>, </u>

Common difference of an AP

\sf{ a2 - a1 }

\sf{ = 14 - 2}

\sf{ = 12}

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

\sf{an = a1 + ( n - 1 )d}

\sf{a5 = 2 + ( 5 - 1 )12}

\sf{a5 = 2 + 4 × 12}

\sf{a5 = 2 + 48}

\sf{\red{a5 = 50}}

Hence, The 5th term of given AP is 50

4 0
2 years ago
Can anybody help with my work
quester [9]
I think the answer is 20.34 I might be wrong someone else could check
5 0
2 years ago
Read 2 more answers
The pearson correlation coefficient measures the strength of the linear association between two variables, x and y, regardless o
Vlada [557]
That is correct do I get the points?
7 0
3 years ago
Need on number 3 plz
Juli2301 [7.4K]

Answer:

Peyton: 6 years old

Matt: 24 years old

Justin: 9 years old

Step-by-step explanation:

P= Peyton   M= Matt   J= Justin

P=J-3

M=4P

J+P+M=39

4J-12=M  4J-12=39-J-P

5J-51=-P    P=J-3

5J-51=-J+3    J=9

P=9-3  P=6

M=4(6)  M=24


6 0
3 years ago
How do I do number 1?
seraphim [82]

Answer:

explain to us please :/

Step-by-step explanation:

5 0
3 years ago
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