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1 year ago

If you select one card at random from a standard deck of 52 cards, what is the probability that the card is a five AND a club?

Mathematics

1 answer:

horsena [70]1 year ago

4 0

Probability is expressed as

number of favorable outcomes/number of total outcomes

The number of cards in a deck is 52(total outcomes)

Recall, there is only 1 five of clubs in a deck of cards(favorable outcomes)

Thus, the probability that the card is a five AND a club is 1/52

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A 3ft child casts a 2ft shadow at the same time a tree casts a shadow that is 6ft long how tall is the tree?

Anettt [7]

Answer:

$h_t=9ft$

Step-by-step explanation:

From the question we are told that:

Height of child $h_c=3ft$

Height of child's shadow $h_c_s=2ft$

Height of tree's shadow $h_t_s=6ft$

Since position of Sun remains constant

Generally the equation for Height of tree h_t mathematically given by

$h_t=f_{ts}\frac{h_c}{h_c_s}$

$h_t=6*\frac{3}{2}$

$h_t=9ft$

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3 years ago

A clothing store marked all of their summer clothing down 50%. A

frozen [14]

The correct answer is 58 yes

6 0

3 years ago

Write an equation in which the quadratic expression 2x^(2)-2x-12equals 0. Show the expression in factored form and explain what

Mnenie [13.5K]

Answer:

Begin by factoring 2 out of 2x^2 - 2x - 12 equals 0:

2(x^2 - x - 6) = 0

2(x - 3)(x + 2) = 0. 2 is never zero, but x-3 and x+2 can each be set = to 0:

This results in x = 3 and x = -2. The equation is true for these two x-values.

Hope this helped :3

-Jazzy <3

3 0

3 years ago

Read 2 more answers

The time rate of change of a rabbit population PP is proportional to the square root of PP. At time t=0t=0 (months) the populati

frosja888 [35]

Answer:

$\frac{dP}{\sqrt{P}} = k dt$

And if we integrate both sides we got:

$2 \sqrt{P} = kt +C$

Where C is a constant., we can rewrite the expression like this:

$\sqrt{P} = \frac{1}{2} (kt +C)$

If we square both sides we got:

$P = \frac{1}{4} (kt +C)^2$

If we use the initial condition we have that:

$P(0) = 100 = \frac{1}{4} (k*0 +C)^2$

And we can solve for C like this:

$400 = C^2$

$C = 20$

And now we can find the derivate of the function and we got:

$P'(t) = 2* \frac{1}{4} (kt + 20) * k$

Using the condition $P'(0) = 10$ we got:

$10 = \frac{1}{2} k (k*0 +20)$

$20 = 20 k$

k= 1

And then the model is defined as:

$P = \frac{1}{4} (t +20)^2$

And for t =12 months we have:

$P(12) = \frac{1}{4} (12 +20)^2 = 256$

Step-by-step explanation:

For this case we cna use the proportional model given by:

$\frac{dP}{dt} = k \sqrt{P}$

Where k is a proportional constant, P the population and the represent the number of months

For this case we know the following initial condition $P(0) =100$ and $P'(0) = 10$

we can rewrite the differential equation like this:

$\frac{dP}{\sqrt{P}} = k dt$

And if we integrate both sides we got:

$2 \sqrt{P} = kt +C$

Where C is a constant., we can rewrite the expression like this:

$\sqrt{P} = \frac{1}{2} (kt +C)$

If we square both sides we got:

$P = \frac{1}{4} (kt +C)^2$

If we use the initial condition we have that:

$P(0) = 100 = \frac{1}{4} (k*0 +C)^2$

And we can solve for C like this:

$400 = C^2$

$C = 20$

And now we can find the derivate of the function and we got:

$P'(t) = 2* \frac{1}{4} (kt + 20) * k$

Using the condition $P'(0) = 10$ we got:

$10 = \frac{1}{2} k (k*0 +20)$

$20 = 20 k$

k= 1

And then the model is defined as:

$P = \frac{1}{4} (t +20)^2$

And for t =12 months we have:

$P(12) = \frac{1}{4} (12 +20)^2 = 256$

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3 years ago

Hi pls help me with this problem

ipn [44]

Answer:

Why is base pairing essential to the process of transcription and translation

3 0

2 years ago