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nasty-shy [4]
1 year ago
13

If you select one card at random from a standard deck of 52 cards, what is the probability that the card is a five AND a club?

Mathematics
1 answer:
horsena [70]1 year ago
4 0

Probability is expressed as

number of favorable outcomes/number of total outcomes

The number of cards in a deck is 52(total outcomes)

Recall, there is only 1 five of clubs in a deck of cards(favorable outcomes)

Thus, the probability that the card is a five AND a club is 1/52

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Determine the relationship between the two triangles and whether or not they can be proven to be congruent.
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Answer:

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Step-by-step explanation:

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Answer:

A

Step-by-step explanation:

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A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys
Luba_88 [7]

Answer:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would earn a certificate of recognition from the fitness association

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the time for this event of a population, and for this case we know the distribution for X is given by:

X \sim N(470,60)  

Where \mu=470 and \sigma=60

NOTE: For this case the fastest 10% is on the lower tail of the distribution

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.9   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.1 of the area on the left and 0.9 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.1 and P(z>-1.28)=0.9

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would  earn a certificate of recognition from the fitness association

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