Question

Will give brainlest to the best answer! This is a 6th grade level question.

Answer 1

Answer:

$253\frac{1}{2} in^2$

Step-by-step explanation:

A cube is a figure consisting of 6 faces with exactly same area. All the edges of a cube have same length.

The surface area of a cube is given by the equation:

$SA=6s^2$ (1)

where

SA is the surface area

s is the length of one edge of the cube

In this problem, we have a box with the shape of a cube; the length of one edge of the cube is:

$s=6\frac{1}{2} in.$

First of all, we rewrite the length of the edge as an improper fraction; we get:

$s=\frac{6\cdot 2 +1}{2}=\frac{13}{2} in.$

Now we use eq(1) to find the surface area of the cube:

$SA=6(\frac{13}{2})^2=6\cdot (\frac{169}{4})=3\cdot \frac{169}{2}=\frac{507}{2} in^2$

Now we want to rewrite it as a mixed fraction, so:

$SA=\frac{507-1}{2}+\frac{1}{2}=253\frac{1}{2} in^2$