(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
---------------------------------------------------------------------------------------
(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
The answer is B, $10,000 is given and is not a variable that can be changed, since there are 150 band students raising money it would be 150x, and the 30,000 is the goal of the fundraiser
Answer:
d
Step-by-step explanation:
The answer is B)
x2+2x−3=0
Factor left side of equation.
(x−1)(x+3)=0
Set factors equal to 0.
x−1=0 or x+3=0
x=1
or
x=−3
