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elena-s [515]
1 year ago
12

ASAP some answer this ASAP

Mathematics
2 answers:
Gekata [30.6K]1 year ago
7 0

Answer:

(-3, 7)

Step-by-step explanation:

minus the x value by 2, minus the y value 3, rule for reflection over line y=-x is (-x, -y), so just swap the signs, and thats your answer.

tatyana61 [14]1 year ago
5 0
This answe would have to be (-3,7)
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The width of a rectangle is twice as long as the length. if the length is increased by 50% and the width is decreased by 20%, th
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3 years ago
If you buy 20 tickets for $6.00, how much are you paying per ticket?
andrew-mc [135]
This is a division problem.

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8 0
3 years ago
Given:
oksian1 [2.3K]

Answer:

9 units

Step-by-step explanation:

By the midsegment theorem,

AB=\dfrac{KN+LM}{2}

Since the ratio LM:KN=1:5, then LM=x,\ KN=5x and

18=\dfrac{x+5x}{2}\\ \\18=\dfrac{6x}{2}\\ \\18=3x\\ \\x=6\\ \\LM=6\ units\\ \\KN=30\ units

Draw two heights LE and MF. Quadrilateral ELMF is a rectangle, then EF = LM = 6 units.

Trapezoid KLMN is isosceles trapezoid (KL = MN), then KE = FN and

KE=FN=\dfrac{KN-EF}{2}=\dfrac{30-6}{2}=12\ units

Consider right triangle KLE. By the Pythagorean theorem,

KL^2=LE^2+KE^2\\ \\15^2=LE^2+12^2\\ \\LE^2=15^2-12^2\\ \\LE^2=225-144=81\\ \\LE=9\ units

3 0
3 years ago
Let Y1 and Y2 have the joint probability density function given by:
Ann [662]

Answer:

a) k=6

b) P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

Step-by-step explanation:

a) if

f (y1, y2) = k(1 − y2), 0 ≤ y1 ≤ y2 ≤ 1,  0, elsewhere

for f to be a probability density function , has to comply with the requirement that the sum of the probability of all the posible states is 1 , then

P(all possible values) = ∫∫f (y1, y2) dy1*dy2 = 1

then integrated between

y1 ≤ y2 ≤ 1 and 0 ≤ y1 ≤ 1

∫∫f (y1, y2) dy1*dy2 =  ∫∫k(1 − y2) dy1*dy2 = k  ∫ [(1-1²/2)- (y1-y1²/2)] dy1 = k  ∫ (1/2-y1+y1²/2) dy1) = k[ (1/2* 1 - 1²/2 +1/2*1³/3)-  (1/2* 0 - 0²/2 +1/2*0³/3)] = k*(1/6)

then

k/6 = 1 → k=6

b)

P(Y1 ≤ 3/4, Y2 ≥ 1/2) = P (0 ≤Y1 ≤ 3/4, 1/2 ≤Y2 ≤ 1) = p

then

p = ∫∫f (y1, y2) dy1*dy2 = 6*∫∫(1 − y2) dy1*dy2 = 6*∫(1 − y2) *dy2 ∫dy1 =

6*[(1-1²/2)-((1/2) - (1/2)²/2)]*[3/4-0] = 6*(1/8)*(3/4)=  9/16

therefore

P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

8 0
3 years ago
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