To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:
![Area = Length \times Width](https://tex.z-dn.net/?f=Area%20%3D%20Length%20%5Ctimes%20Width)
<u>Rectangle (a)</u>
![Area = 4x \times 4](https://tex.z-dn.net/?f=Area%20%3D%204x%20%5Ctimes%204)
![Area = 16x](https://tex.z-dn.net/?f=Area%20%3D%2016x)
<u>Rectangle (b)</u>
![Area = 11 \times x](https://tex.z-dn.net/?f=Area%20%3D%2011%20%5Ctimes%20x)
![Area = 11x](https://tex.z-dn.net/?f=Area%20%3D%2011x)
<u>Rectangle (c)</u>
![Area = 2 \times 8x](https://tex.z-dn.net/?f=Area%20%3D%202%20%5Ctimes%208x)
![Area = 16x](https://tex.z-dn.net/?f=Area%20%3D%2016x)
<u>Rectangle (d)</u>
![Area = 16x \times 1](https://tex.z-dn.net/?f=Area%20%3D%2016x%20%5Ctimes%201)
![Area = 16x](https://tex.z-dn.net/?f=Area%20%3D%2016x)
Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
Read more about areas of rectangles at:
brainly.com/question/14383947
We are looking for a new number which is 30 less than 10. We will get the new number by subtracting 30 from 10. We write it down as: 10-30=-20
And finally the solution for: What number is 30 less than 10? is -20
Hope this helps!!
Answer:
$600,000
Step-by-step explanation:
GIven;
Alex had $750,000 he lost 80%
To Find;
How many dollars did he lose
Solve;
$750,000 * 80% = 600,000
Hence, Alex lost $600,000.
<em>~Learn with Lenvy~</em>
The answer is 21x-28 hope it helps