Name two rays that contain the following line segments: • QP• SU (the options for QP are: rays PU; QP; TQ; NP; MS)(the options f
or SU are: Rays MT; UP; RU; SN; SU).
1 answer:
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Fist, in the equation y=mx+b, b is the y-intercept. The y-intercept is the poin on the line that crosses the x-axis; the y-intercept is the value of yThese equations follow that format.
Y=mx+b
y
3x-4. <-----In this equation, the slope(m)=3 b= -4.
On the graph, we can see that the line crosses the x-axis at y=-4. Knowing that, we can eliminate the answer choices with +4 in the inequality.
The next step, is to pick an (x,y) coordinate that is in the shaded region and plug it into the remaining 2 inequalities. Which ever inequality is true after you solve it, that is the correct answer.
For example, I'll choose to plug in (-4,4) into the y 3x-4.
y 3x-4.
(4) (3(-4))-4.
(4) (-12)-4.
(4) -16
So, this statement is true becasue -16 is less than positive 4. Therefore, the correct answer would be y 3x-4. Hope that helped! Comment back with any further questions!
Y=mx+b
y
On the graph, we can see that the line crosses the x-axis at y=-4. Knowing that, we can eliminate the answer choices with +4 in the inequality.
The next step, is to pick an (x,y) coordinate that is in the shaded region and plug it into the remaining 2 inequalities. Which ever inequality is true after you solve it, that is the correct answer.
For example, I'll choose to plug in (-4,4) into the y
y
(4)
(4)
(4)
So, this statement is true becasue -16 is less than positive 4. Therefore, the correct answer would be y