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Luden [163]
3 years ago
10

2/3(5x-6)=6 solve for x

Mathematics
1 answer:
alisha [4.7K]3 years ago
4 0

Answer:

x=3

Step-by-step explanation:

There's many ways you can begin this, I prefer getting rid of the fraction first.

Multiply both sides by 3/2 (yes, I switched it on purpose)

You get. . .

5x-6 = 9

To isolate the 5x, add 6 to both sides

5x = 15

Divide both sides by 5 and you get . . .

x=3

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Marianna [84]

Answer:

3

Step-by-step explanation:

Get rid of fractions:

Multiply the whole equation, i.e. all terms both sides of the equals sign, by the denominator or the lowest common multiple of all denominators if there are multiple fractions in the equation;

In this case, only one term is a fraction and therefore has a denominator (i.e. 7), so it is this number we multiply the equation by to get:

7(y) = 7(-³/₇.x) + 7(3)

7y = -3x + 21

3x + 7y = 21

5 0
2 years ago
11. Identify the properties below.<br> a. 5 + 6 = 6 + 5<br> b. 7 + (3 + 9) = (7 + 9) + 3
jenyasd209 [6]
A is commutative property
B is associative property
Explanation:
5 0
3 years ago
How many meters are in a 5 km race
o-na [289]

Answer:

5000 meters

Step-by-step explanation:

1 km = 1000 m

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6 0
3 years ago
Read 2 more answers
57 is 13.5% of what number?
kondaur [170]
Let, the number = x
It would be: x * 0.135 = 57
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Hope this helps!
6 0
3 years ago
Find the first four positive values of arccos(0.7). I know how to get the first, but as for the rest, I am lost.
Mandarinka [93]
Now cos⁻¹(0.7) is about 45.6°, that's on the first quadrant.

keep in mind that the inverse cosine function has a range of [0, 180°], so any angles it will spit out, will be on either the I quadrant where cosine is positive or the II quadrant, where cosine is negative.

however, 45.6° has a twin, she's at the IV quadrant, where cosine is also positive, and that'd be 360° - 45.6°, or 314.4°.

now, those are the first two, but we have been only working on the [0, 360°] range.... but we can simply go around the circle many times over up to 720° or 72000000000° if we so wish, so let's go just one more time around the circle to find the other fellows.

360° + 45.6° is a full circle and 45.6° more, that will give us the other angle, also in the first quadrant, but after a full cycle, at 405.6°.

then to find her twin on the IV quadrant, we simply keep on going, and that'd be at 360° + 360° - 45.6°, 674.4°.

and you can keep on going around the circle, but only four are needed this time only.
6 0
3 years ago
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