Question

Quadrilateral ABCD?​

Answer 1

The given quadrilateral is a kite.

Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)

Firstly, we find the distance between AD and DC

AD = $\sqrt{(7 - 2)^{2} + (4 - 4)^{2} }$

⇒ AD = $\sqrt{5^{2} }$

⇒ AD = 5

DC = $\sqrt{(7 - 7)^{2} + (4 - (-1))^{2} }$

⇒ DC = $\sqrt{5^{2} }$

⇒ DC = 5

Hence, AD = DC = 5

Now, find the distance between AB and BC

AB = $\sqrt{(-2 - 2)^{2} + (-5 - 4)^{2} }$

⇒ AB = $\sqrt{(-4)^{2} + (-9)^{2} }$

⇒ AB = $\sqrt{16 + 81}$

⇒ AB = $\sqrt{97}$

BC = $\sqrt{(7 - (-2))^{2} + (-1 - (-5))^{2} }$

⇒ BC = $\sqrt{9^{2} + 4^{2} }$

⇒ BC = $\sqrt{81 + 16}$

⇒ BC = $\sqrt{97}$

Hence, AB = BC = √97

In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.

Hence, it follows the property of kite.

For more questions on quadrilateral, visit:

brainly.com/question/23935806

#SPJ9