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3 years ago

If f (x)=x2and g(x)=x+6find g(f(0))

Mathematics

2 answers:

bija089 [108]3 years ago

7 0

Answer:

g(f(x))=6x2−30

Explanation:

g(f(x)) mains you put the function f(x) into the function g(x)

g(f(x))=6(x2−5))g(f(x))=6x2-30

Marysya12 [62]3 years ago

4 0

Answer:

g(f(0)) = 6

Step-by-step explanation:

Evaluate f(0 ) and substitute this value into g(x)

f(0) = 0² = 0 and

g(0) = 0 + 6 = 6

⇒ g(f(0)) = 6

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Solve the equation: k^2+5k+13=0

mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\$

From the question

a = 1 , b = 5 , c = 13

So we have

$k = \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)} \\ = \frac{ - 5 \pm \sqrt{25 - 52} }{2} \\ = \frac{ - 5 \pm \sqrt{ - 27} }{2} \: \: \: \: \: \: \\ = \frac{ - 5 \pm3 \sqrt{3} \: i}{2} \: \: \: \: \: \:$

<u>Separate the solutions</u>

$k_1 = \frac{ - 5 + 3 \sqrt{3} \: i }{2} \: \: \: \: or \\ k_2 = \frac{ - 5 - 3 \sqrt{3} \: i}{2}$

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

$k_1 = - \frac{5}{2} + \frac{3 \sqrt{3} }{2} \: i \: \: \: \: or \\ k_2 = - \frac{5}{2} - \frac{3 \sqrt{3} }{2} \: i$

Hope this helps you

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3 years ago

Reba needs to simplify the expression below. 6 1/2+3.5x2-7 divided by 3 Which operation should she perform first?

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Step-by-step explanation:

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2 years ago

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use the pythagorean theorem twice
alrighty
so
remember for legs length a and b and hytponuse c in a right triangle
a²+b²=c²

we need AD and DC

so
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