3logs at 3logs C-15log abbCondense each expression to a single logarithm

1 answer:

8 0

$\begin{gathered} 3\log _9a+3\log _9c-15\log _9b \\ \log _9a^3+\log _9c^3-\log _9b^{15} \\ \log _9(a^3b^3)-\log _9b^{15} \\ \log _9(\frac{a^3b^3}{b^{15}}) \end{gathered}$

You might be interested in

Find the standard deviation for the set of data. (17,26,28,9,30, 29,6,21,23}

gogolik [260]

Using it's concept, the standard deviation for the given data-set is of 8.22.

<h3>What are the mean and the standard deviation of a data-set?</h3>

The mean of a data-set is given by the <u>sum of all values in the data-set, divided by the number of values</u>.

The standard deviation of a data-set is given by the square root of the <u>sum of the differences squared between each observation and the mean, divided by the number of values</u>.

The mean for this problem is:

M = (17 + 26 + 28 + 9 + 30 + 29 + 6 + 21 + 23)/9 = 21

Hence the standard deviation is:

$S = \sqrt{\frac{(17-21)^2 + (26-21)^2 + (28-21)^2 + \cdots + (21-21)^2 + (23-21)^2}{9}} = 8.22$