Answer: its the first one "opposite sides with equal length"
-83/40
There is no way this is college math lol
To find the solutions, set the equation equal to 0. You get
. We are going to factor our things that both terms have in common, a 2, and an x. This gives you
. How do you know this is true? If you distribute back out, you get the same as the original problem.
Now set these both equal to zero. 2x = 0, 2x + 17 = 0. Divide both sides by 2, you get one solultion of x = 0. For the other solution, subtract 17 from both sides; 2x = - 17. Divide by 2, x = -17/2
Your solutions are x = {- 17/2, 0}
To check, plug these back into the original equation to see if they equal zero. 4(0)^2 + 34(0) = 0 + 0 = 0
4(- 17/2)^2 + 34(- 17/2) = 289 + (- 289) = 289 - 289 = 0
Answer:
D
and it is correct because it is
Answer:
Step-by-step explanation:
Since, ΔBCM ≅ ΔZYR,
∠B ≅ ∠Z
∠C ≅ ∠Y
∠M ≅ ∠R
And BC ≅ ZY
CM ≅ YR
BM ≅ ZR
a). CM = YR = 11 m
b). BM = RZ = 15 m
c). YZ = BC = 8 m
d). m∠B = m∠Z = 45°
e). m∠M = 180° - [m(∠B) + m(∠C)]
= 180° - (45 + 103)°
= 180° - 148°
= 32°
f). m∠Y = m∠C = 103°